Log out Go to App
Go to App

Learning Materials

Features

Discover

Chapter 9: Problem 64

Write Lewis structures for the reaction $$ \mathrm{AlCl}_{3}+\mathrm{Cl}^{-} \longrightarrow \mathrm{AlCl}_{4}^{-} $$ What kind of bond is between \(\mathrm{Al}\) and \(\mathrm{Cl}\) in the product?

Short Answer

Expert verified
In the product, \(AlCl_4^{-}\), the bond between Al and Cl is an ionic bond.

Step by step solution

01

Interpret the chemical equation

Looking at the equation \(AlCl_3 + Cl^- \rightarrow AlCl_4^-\), it shows that an aluminum chloride molecule is interacting with a chloride ion to form a tetrahedral aluminum chloride ion.
02

Drawing the Lewis structure of Initial Reactants

Al (Aluminum) has 3 valence electrons and Cl (Chloride) has 7 valence electrons. In \(AlCl_3\), Al utilizes its 3 valence electrons to form 3 bonds with three separate Cl atoms, each providing an electron, making it a neutral species. For \(Cl^{-}\), adding an extra electron to the 7 valence electrons of Cl makes it 8, which completes its octet, making it a negatively charged ion.
03

Drawing the Lewis Structure for the Final Product

The product of the reaction is \(AlCl_4^{-}\). The incoming Cl^- forms a bond with the existing aluminum ion by providing one additional electron. Now, the aluminum atom has an electron octet but carries a negative charge because it takes one electron more than it has in its valence shell.
04

Identifying the type of bond

The bond between Al and Cl in the product \(AlCl_4^{-}\) are ionic in nature because of the transfer of electrons from chloride ions to the aluminum ion.

Unlock Step-by-Step Solutions & Ace Your Exams!

  • Full Textbook Solutions

    Get detailed explanations and key concepts

  • Unlimited Al creation

    Al flashcards, explanations, exams and more...

  • Ads-free access

    To over 500 millions flashcards

  • Money-back guarantee

    We refund you if you fail your exam.

Start your free trial

Over 30 million students worldwide already upgrade their learning with Vaia!

One App. One Place for Learning.

All the tools & learning materials you need for study success - in one app.

Get started for free

Most popular questions from this chapter

From these data, calculate the average bond enthalpy for the \(\mathrm{N}-\mathrm{H}\) bond: $$ \begin{array}{cl} \mathrm{NH}_{3}(g) \longrightarrow \mathrm{NH}_{2}(g)+\mathrm{H}(g) & \Delta H^{\circ}=435 \mathrm{~kJ} / \mathrm{mol} \\ \mathrm{NH}_{2}(g) \longrightarrow \mathrm{NH}(g)+\mathrm{H}(g) & \Delta H^{\circ}=381 \mathrm{~kJ} / \mathrm{mol} \\ \mathrm{NH}(g) \longrightarrow \mathrm{N}(g)+\mathrm{H}(g) & \Delta H^{\circ}=360 \mathrm{~kJ} / \mathrm{mol} \end{array} $$

Without referring to Figure 9.1 , write Lewis dot symbols for atoms of the following elements: (a) Be, (b) \(\mathrm{K},\) (c) \(\mathrm{Ca},\) (d) \(\mathrm{Ga},\) (e) \(\mathrm{O},\) (f) \(\mathrm{Br},(\mathrm{g}) \mathrm{N},(\mathrm{h}) \mathrm{I},\) (i) \(\mathrm{As}\), (j) F.

In the vapor phase, beryllium chloride consists of discrete molecular units \(\mathrm{BeCl}_{2}\). Is the octet rule satisfied for Be in this compound? If not, can you form an octet around Be by drawing another resonance structure? How plausible is this structure?

What is a Lewis dot symbol? To what elements does the symbol mainly apply?

Specify which compound in the following pairs of ionic compounds has the higher lattice energy: (a) \(\mathrm{KCl}\) or \(\mathrm{MgO},\) (b) \(\mathrm{LiF}\) or \(\mathrm{LiBr}\) (c) \(\mathrm{Mg}_{3} \mathrm{~N}_{2}\) or \(\mathrm{NaCl}\). Explain your choice.
See all solutions

Recommended explanations on Chemistry Textbooks

Inorganic Chemistry

Read Explanation

The Earths Atmosphere

Read Explanation

Kinetics

Read Explanation

Nuclear Chemistry

Read Explanation

Making Measurements

Read Explanation

Ionic and Molecular Compounds

Read Explanation
View all explanations

What do you think about this solution?

We value your feedback to improve our textbook solutions.

Study anywhere. Anytime. Across all devices.

Sign-up for free