Chapter 9: Problem 99

Draw Lewis structures for these organic molecules, in each of which there is one \(\mathrm{C}=\mathrm{C}\) bond and the rest of the carbon atoms are joined by \(\mathrm{C}-\mathrm{C}\) bonds: \(\mathrm{C}_{2} \mathrm{H}_{3} \mathrm{~F}, \mathrm{C}_{3} \mathrm{H}_{6}, \mathrm{C}_{4} \mathrm{H}_{8}\).

Short Answer

Expert verified

The Lewis structures for the given organic molecules, showing exactly one carbon-carbon double bond (\(\mathrm{C}=\mathrm{C}\)) in each molecule are: For \(\mathrm{C}_{2} \mathrm{H}_{3} \mathrm{~F}\), it's F-C=C-H with the double bond between the two carbons and two H atoms bonded to the second carbon. For \(\mathrm{C}_{3} \mathrm{H}_{6}\), it's C=C-C with two H atoms bonded to each carbon. For \(\mathrm{C}_{4} \mathrm{H}_{8}\), it's C-C=C-C with three H atoms bonded to the first and fourth carbons, and one H atom bonded to the second and third carbons.

Step by step solution

Draw Lewis Structure for \(\mathrm{C}_{2} \mathrm{H}_{3} \mathrm{~F}\)

Each carbon (C) atom can form 4 bonds, each hydrogen (H) atom forms 1 bond, and fluorine (F) forms 1 bond. First, draw two carbon atoms connected by a double bond to account for the \(\mathrm{C}=\mathrm{C}\) requirement. Arrange the 1 F and 3 H atoms around the carbon atoms to ensure the octet rule is satisfied. The Lewis structure can be represented as: F-C=C-H with two H atoms bonded to the second carbon.

Draw Lewis Structure for \(\mathrm{C}_{3} \mathrm{H}_{6}\)

In this case, given there are 3 carbon atoms and 6 hydrogen atoms, connect the 3 carbon atoms together with one double bond and one single bond to satisfy the \(\mathrm{C}=\mathrm{C}\) requirement. Then, distribute the 6 H atoms around the 3 carbon atoms to satisfy the octet rule. The Lewis structure can be represented as: C=C-C, with the first two carbon atoms each having two H atoms bonded to them, and the third carbon atom having two H atoms bonded to it.

Draw Lewis Structure for \(\mathrm{C}_{4} \mathrm{H}_{8}\)

For \(\mathrm{C}_{4} \mathrm{H}_{8}\), connect the 4 carbon atoms in a chain with one double bond and two single bonds to account for the \(\mathrm{C}=\mathrm{C}\) requirement. Then, distribute the 8 hydrogen atoms around the 4 carbon atoms to satisfy the octet rule. The Lewis structure can be represented as: C-C=C-C, with the first and last carbon atoms each having three H atoms bonded to them, and the second and third carbon atoms each having one H atom bonded to them.

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Draw Lewis structures for these organic molecules, in each of which there is one \(\mathrm{C}=\mathrm{C}\) bond and the rest of the carbon atoms are joined by \(\mathrm{C}-\mathrm{C}\) bonds: \(\mathrm{C}_{2} \mathrm{H}_{3} \mathrm{~F}, \mathrm{C}_{3} \mathrm{H}_{6}, \mathrm{C}_{4} \mathrm{H}_{8}\).

Short Answer

Step by step solution

Draw Lewis Structure for \(\mathrm{C}_{2} \mathrm{H}_{3} \mathrm{~F}\)

Draw Lewis Structure for \(\mathrm{C}_{3} \mathrm{H}_{6}\)

Draw Lewis Structure for \(\mathrm{C}_{4} \mathrm{H}_{8}\)

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