Why is the molar enthalpy of vaporization of a substance much higher than the molar enthalpy of fusion?

Short Answer

Expert verified
The molar enthalpy of vaporization for a substance is significantly higher than the molar enthalpy of fusion due to the higher energy requirement to overcome all the intermolecular attractions and transition from a liquid to a gaseous state, creating a high level of disorder.

Step by step solution

01

Definition of Molar Enthalpy of Fusion

The molar enthalpy of fusion refers to the amount of energy necessary, per mole of the substance, to change the substance from a solid to a liquid state at its melting point under standard conditions.
02

Definition of Molar Enthalpy of Vaporization

The molar enthalpy of vaporization is the quantity of energy required, per mole of the substance, to change the substance from a liquid to a gaseous state at its boiling point under standard options. This transition to the gaseous state involves breaking intermolecular attractions in the liquid, making the molecules disordered.
03

Contrast between Molar Enthalpy of Fusion and Vaporization

In the case of molar enthalpy of fusion, some intermolecular attractions must be broken to permit a slight increase in disorder (from rigid lattice in solid to a bit more randomness in liquid). However, to achieve vaporization, much more energy is needed to overcome the entirety of the intermolecular attractions, as this process leads to a very high increase in disorder (from close contact in liquid to complete freedom in gas). This results in the vaporization's molar enthalpy being higher than fusion's.

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