Chapter 11: Problem 43

Calculate the melting point of acetic acid at standard pressure. The enthalpy of fusion of acetic acid is \(11.54 \mathrm{kJ} / \mathrm{mol},\) and the entropy of fusion is 39.8 \(\mathrm{J} / \mathrm{mol} \cdot \mathrm{K}\) .

Short Answer

Expert verified

The melting point of acetic acid at standard pressure is approximately 289.95 Kelvin.

Step by step solution

Understand the Given Values

The problem statement gives us the value of enthalpy and entropy of fusion. The enthalpy of fusion \(\Delta H_f\) is 11.54 kJ/mol. For calculations, convert this to J/mol by multiplying by 1000, getting 11540 J/mol. The entropy of fusion \(\Delta S_f\) is given as 39.8 J/mol*K.

Using the Gibbs Free Energy equation

We now use the equation \(\Delta G = \Delta H - T\Delta S = 0\) at the melting point. We are looking for the temperature \(T\), so we need to rearrange the equation, which results in \(T = \Delta H/\Delta S\).

Plug in Given Values

Now we can substitute the values for the enthalpy and entropy of fusion into the expression from step 2. Doing this, we find: \(T = 11540/39.8 = 289.95\) Kelvin.

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Calculate the melting point of acetic acid at standard pressure. The enthalpy of fusion of acetic acid is \(11.54 \mathrm{kJ} / \mathrm{mol},\) and the entropy of fusion is 39.8 \(\mathrm{J} / \mathrm{mol} \cdot \mathrm{K}\) .

Short Answer

Step by step solution

Understand the Given Values

Using the Gibbs Free Energy equation

Plug in Given Values

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