How many moles of argon are there in \(20.0 \mathrm{L},\) at \(25^{\circ} \mathrm{C}\) and 96.8 \(\mathrm{kPa}\) ?

Short Answer

Expert verified
The number of moles of argon is approximately 0.785 mol.

Step by step solution

01

Convert all units to the standard units

The standard units for the Ideal Gas Law are volume in litres (L), pressure in kilopascals (kPa), and temperature in Kelvin (K). Here, pressure, \(P = 96.8\ kPa\) and volume, \(V = 20.0\ L\) are already in standard units, but the temperature must be converted from Celsius to Kelvin. The formula to convert Celsius to Kelvin is \(K = °C + 273.15\), so, \(T = 25°C + 273.15 = 298.15 K\).
02

Substituting the values into the Ideal Gas Law

Rearrange the Ideal Gas Law to solve for n, \( n = \frac{PV}{RT}\), and then substitute P=96.8 kPa, V=20.0 L, R = 8.314 L.kPa/K.mol (R is a constant), and T=298.15 K into the formula. This gives: \(n = \frac{96.8\ kPa \times 20.0\ L}{8.314 \ L.kPa/K.mol \times 298.15\ K}\).
03

Calculate the number of moles

Perform the calculation to find the number of moles. The units of kPa, L, and K all cancel to leave only moles (mol), which is the desired unit for n.

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