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Chapter 13: Problem 44

What is the molarity of a solution that contains 20.0 g \(\mathrm{NaOH}\) in 2.00 \(\mathrm{L}\) of solution?

Short Answer

Expert verified
The molarity of the solution is 0.250 M.

Step by step solution

01

Convert grams to moles

The first step is to convert the given mass of the substance (\(NaOH\)), from grams into moles. This is done by using the molar mass of \(NaOH\), which is 39.997 g/mol. From this, we can determine the number of moles (n) using the formula \(n = weight / molar \, mass\). Applying this formula, the number of moles of \(NaOH\) is \(n = 20.0 \, g / 39.997 \, g/mol = 0.500 \, mol\).
02

Calculate the molarity

The next step is to calculate the molarity, which is the amount of substance per unit volume of the solution. The formula for molarity (M) is\(M = n / V\), where n is the number of moles and V is the volume in liters. Substituting the given values, the molarity of the solution is \(M = 0.500 \, mol / 2.00 \, L = 0.250 \, mol/L\).

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