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Chapter 13: Problem 45

Calculate the molarity of a \(\mathrm{H}_{3} \mathrm{PO}_{4}\) solution of 6.66 \(\mathrm{g}\) in 555 \(\mathrm{mL}\) of solution.

Short Answer

Expert verified
The molarity of the \(\mathrm{H}_{3} \mathrm{PO}_{4}\) solution is 0.122 M.

Step by step solution

01

Calculate moles of \(\mathrm{H}_{3} \mathrm{PO}_{4}\)

Use the formula: moles = mass/Molecular mass. Substituting the given mass (6.66g) and the molecular mass of \(\mathrm{H}_{3} \mathrm{PO}_{4}\) (98 g/mol), we get: moles = 6.66 g/98 g/mol = 0.068 mol.
02

Convert milliliters to liters

1 litre contains 1000 milliliters. Therefore, to convert the volume of the solution from milliliters to liters, divide the volume in milliliters by 1000. We have: Volume = 555 mL/1000 = 0.555 L.
03

Calculate molarity

Use the formula to find molarity: Molarity (M) = moles of solute/volume of solution in liters. Substitute in our variables: Molarity = 0.068 mol/0.555 L = 0.122 M.

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