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Chapter 13: Problem 46

Calculate the mass of \(\mathrm{NaOH}\) in 65.0 \(\mathrm{mL}\) of 2.25 \(\mathrm{M}\) solution.

Short Answer

Expert verified
The mass of \(NaOH\) in the 65.0 mL of 2.25 M solution is approximately 5.85 g.

Step by step solution

01

Convert volume to liters

First, convert the volume of the solution from milliliters to liters. There are 1000 milliliters in 1 liter. Therefore, the volume in liters is \( 65.0\, \mathrm{mL} \div 1000 = 0.065 \,\mathrm{L} \).
02

Calculate moles of \(NaOH\)

Next, use the molarity to find the number of moles of \(NaOH\). Molarity (\(M\)) is defined as moles of solute per liter of solution. Therefore, the number of moles of \(NaOH\) can be calculated as \( \text{moles of}\, NaOH = 0.065 \,\mathrm{L} \times 2.25\, \mathrm{M} = 0.14625\, \mathrm{mol}\).
03

Calculate mass of \(NaOH\)

Because we know that one mole of \(NaOH\) has a mass of about 40 grams (23 g from Na, 16 g from O and 1 g from H), the mass of 0.14625 mol of \(NaOH\) can be calculated as \( \text{mass of} \, NaOH = 0.14625\, \mathrm{mol} \times 40\, \mathrm{g/mol} = 5.85\, \mathrm{g}\).

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