Calculate the mass of LiF in 100.0 \(\mathrm{mL}\) of 0.100 \(\mathrm{M}\) solution.

Short Answer

Expert verified
The mass of LiF in 100.0 \(\mathrm{mL}\) of 0.100 \(\mathrm{M}\) solution is 0.25938 g.

Step by step solution

01

Understand the problem

In this problem, it is important to understand what molarity (M) means. Molarity is the number of moles of solute per litre of solution.
02

Calculate the number of moles

The problem provides the volume of solution and its molarity. The volume is 100.0 ml, which is equivalent to 0.1L (as 1L = 1000 ml). The molarity is 0.100 M. Since molarity (M) = moles / volume (L), we can calculate the number of moles of LiF by multiplying the volume by the molarity. Thus, moles of LiF = volume (in L) * molarity = 0.1L * 0.100 M = 0.01 moles.
03

Calculate the mass of LiF

Once the number of moles is determined, we can calculate the mass using the molar mass of LiF. The molar mass of LiF = mass of Li + mass of F = 6.94 g/mol + 18.998 g/mol = 25.938 g/mol. Then, we multiply the number of moles by the molar mass to find the mass. So, mass = no. of moles * molar mass = 0.01 mol * 25.938 g/mol = 0.25938 g.

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