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Chapter 14: Problem 4

What are ligands?

Short Answer

Expert verified
Ligands are ions or molecules that bind to a central metal atom to create a coordination complex. They have a particular attraction to their corresponding molecule or ion due to electromagnetic forces. Examples include water, ammonia, cyanide, and chlorine ions.

Step by step solution

01

Understand the Term

A ligand is an ion or molecule that binds to a central metal atom to form a coordination complex. It's a substance that could produce a complex molecule with a metal atom.
02

Function of Ligands

In ligand binding, the ligand and its corresponding molecule or ion have a certain level of attraction, which is caused by electromagnetic force. It can help stabilize the molecule and determine its reactivity.
03

Examples of Ligands

Examples of ligands can include water (H2O), ammonia (NH3), cyanide (CN-) and chlorine ions (Cl-) among others.

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Most popular questions from this chapter

The ionic substance \(\mathrm{T}_{3} \mathrm{U}_{2}\) ionizes to form \(\mathrm{T}^{2+}\) and \(\mathrm{U}^{3-}\) ions. The solubility of \(\mathrm{T}_{3} \mathrm{U}_{2}\) is \(3.77 \times 10^{-20} \mathrm{mol} / \mathrm{L}\) . What is the value of the solubility-product constant?

Imagine the following hypothetical reaction, taking place in a sealed, rigid container, to be neither exothermic nor endothermic. $$\mathrm{A}(g)+\mathrm{B}(g) \rightleftarrows \mathrm{C}(g) \quad \Delta H=0$$ Would an increase in temperature favor the forward reaction or the reverse reaction? (Hint: Recall the gas laws.)

In general, which reaction (forward, reverse, or neither) is favored if the value of \(K\) at a specified temperature is a. equal to 1\(?\) b. very small? c. very small?

Write the \(K_{e q}\) expressions for the following reactions: $$\begin{array}{c}{\mathbf{a} \cdot 4 \mathrm{H}_{3} \mathrm{O}^{+}(a q)+2 \mathrm{Cl}^{-}(a q)+\mathrm{MnO}_{2}(s) \rightleftarrows} \\\ {\mathrm{Mn}^{2+}(a q)+6 \mathrm{H}_{2} \mathrm{O}(l)+\mathrm{Cl}_{2}(g)} \\\ {\text { b. } \mathrm{As}_{4} \mathrm{O}_{6}(s)+6 \mathrm{H}_{2} \mathrm{O}(l) \rightleftarrows 4 \mathrm{H}_{3} \mathrm{AsO}_{3}(a q)}\end{array}$$

Changes in the concentrations of the reactants and products at equilibrium have no effect on the value of the equilibrium constant. Explain this statement.
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