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Chapter 14: Problem 58

What is the change in the rate of the forward reaction after the reaction is at equilibrium?

Short Answer

Expert verified
The change in the rate of the forward reaction once the reaction has reached equilibrium is zero.

Step by step solution

01

Understand What Chemical Equilibrium Represents

Equilibrium in a chemical reaction is a state where the rate of the forward reaction (reactants turning into products) is equal to the rate of the reverse reaction (products turning into reactants). In other words, at equilibrium, the concentrations of reactants and products remain constant over time, although the reactions themselves still continue to occur.
02

Relate the Rate of the Forward Reaction to Equilibrium

Once a reaction has reached chemical equilibrium, the rates of the forward and reverse reactions remain constant. The rate of the forward reaction is equal to the rate of the reverse reaction at this point.
03

Determine the Change in the Rate of the Forward Reaction

Since the rate of the forward reaction is constant once equilibrium is reached, the change in the rate of the forward reaction, or the rate at which this rate is increasing or decreasing, would be zero. The rate does not increase, nor does it decrease. It remains constant.

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Most popular questions from this chapter

Why might an industrial process be operated at high temperature even though the reaction is more favorable at lower temperatures?

In the context of Le Chatelier's principle, what is a "stress"? List the stresses that affect chemical equilibria.

What is the distinction between a static equilibrium and a dynamic equilibrium? In which class do chemical equilibria fit?

The solubility of cobalt \((\mathrm{II})\) sulfide, coS, is \(1.7 \times 10^{-13} \mathrm{M}\) . Calculate the solubility product constant for \(\mathrm{CoS} .\)

The ionic substance \(\mathrm{T}_{3} \mathrm{U}_{2}\) ionizes to form \(\mathrm{T}^{2+}\) and \(\mathrm{U}^{3-}\) ions. The solubility of \(\mathrm{T}_{3} \mathrm{U}_{2}\) is \(3.77 \times 10^{-20} \mathrm{mol} / \mathrm{L}\) . What is the value of the solubility-product constant?
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