Explain why, even though a collision may have energy in excess of the activation energy, reaction may not occur.

Short Answer

Expert verified
Even though a collision may have energy in excess of the activation energy, reaction may not occur because for a reaction to take place, it's not sufficient for molecules to just collide with the required activation energy. A proper orientation at the time of collision is also needed. The reactant molecules need to be aligned in a way that allows their reactive parts to come into contact.

Step by step solution

01

Understand the concept of Activation Energy

Activation Energy is the minimum amount of energy that is necessary for a chemical reaction to occur. It is the 'energy barrier' that reactants must overcome so they can be transformed into products.
02

Know about Collision Theory

For a reaction to occur, molecules, atoms or ions must collide with a certain minimum energy and appropriate orientation. This is the baseline of Collision Theory.
03

Acknowledge the importance of the right orientation

Even if the colliding particles have energy more than or equal to the activation energy, a reaction may not occur if the molecules are not oriented correctly when they collide. The reactant molecules must be aligned in such a way that the reactive parts of the molecules come into contact.

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Key Concepts

These are the key concepts you need to understand to accurately answer the question.

Understanding Collision Theory
Collision theory is at the core of why chemical reactions occur. It explains the dynamics behind reactions and provides a scientific basis for understanding reaction rates. According to this theory, particles such as atoms, ions, or molecules must collide in order to react. But it's not just any collision that will do; these particles must collide with sufficient energy, known as the activation energy, which is necessary for breaking the original bonds so new ones can form.

The theory also emphasizes that only a percentage of collisions result in a reaction. This is because only those collisions with energy greater than or equal to the activation energy, as well as proper orientation, can lead to successful reactions. It's akin to the idea that only a key with the right shape and force can turn a lock. If either element is off, the lock won't turn, just as a chemical reaction won't proceed.
Chemical Kinetics and Activation Energy

Rate of Reactions

Chemical kinetics is about understanding the speeds (or rates) at which reactions occur and the factors that affect these rates. Activation energy is one crucial factor. Think of it like a hill that reactants must climb over to transform into products. The height of this hill dictates how much energy is needed for a reaction to proceed.

Imagine pushing a ball up a hill—the higher the hill, the more effort you need. Similarly, in chemical kinetics, the higher the activation energy, the slower the reaction rate, as fewer particles will have enough energy to reach the top and 'roll down' to products. The relationship between the rate of reaction and activation energy is fundamental in predicting how fast a reaction will occur under different conditions.
The Significance of Reaction Orientation
The concept of reaction orientation adds another layer to our understanding of why reactions occur or fail to occur. As previously mentioned, even if particles collide with energy above the threshold of activation energy, they must be oriented in a particular way for a successful reaction to take place. It's a bit like building with blocks—if the blocks don't fit together in the correct way, you cannot build your structure.

The specific atomic or molecular arrangement required for a reaction to proceed is crucial, as it ensures that the right atoms bond together. Location, position, and timing all play a part—imagine a puzzle where each piece must align perfectly for completion. This is a vivid analogy for reaction orientation because, without correct alignment, no product is formed, even with enough energy.

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Most popular questions from this chapter

What is a mechanism, and what is its rate-determining step?

The graphing calculator can run a program that can tell you the order of a chemical reaction, provided you indicate the reactant concentrations and reaction rates for two experiments involving the same reaction. Go to Appendix C. If you are using a TI-83 Plus, you can download the program RXNORDER and run the application as directed. If you are using another calculator, your teacher will provide you with key-strokes and data sets to use. At the prompts, enter the reactant concentrations and reaction rates. Run the program as needed to find the order of the following reactions. (All rates are given in M/s.) a. \(2 \mathrm{N}_{2} \mathrm{O}_{5}(g) \rightarrow 4 \mathrm{NO}_{2}(g)+\mathrm{O}_{2}(g)\) \(\mathrm{N}_{2} \mathrm{O}_{5} :\) conc. \(1=0.025 \mathrm{M} ;\) conc. \(2=0.040 \mathrm{M}\) rate \(1=8.1 \times 10^{-5} ;\) rate \(2=1.3 \times 10^{-4}\) b. \(2 \mathrm{NO}_{2}(g) \rightarrow 2 \mathrm{NO}(g)+\mathrm{O}_{2}(g)\) \(\mathrm{NO}_{2} : \mathrm{conc.} 1=0.040 \mathrm{M} ; \mathrm{conc} .2=0.080 \mathrm{M}\) rate \(1=0.0030 ;\) rate \(2=0.012\) c. \(2 \mathrm{H}_{2} \mathrm{O}_{2}(g) \rightarrow 2 \mathrm{H}_{2} \mathrm{O}(g)+\mathrm{O}_{2}(g)\) \(\mathrm{H}_{2} \mathrm{O}_{2} :\) conc. \(1=0.522 \mathrm{M} ;\) conc. \(2=0.887 \mathrm{M}\) rate \(1=1.90 \times 10^{-4} ;\) rate \(2=3.23 \times 10^{-4}\) d. \(2 \mathrm{NOBr}(g) \rightarrow 2 \mathrm{NO}(g)+\mathrm{Br}_{2}(g)\) NOBr: conc. \(1=1.27 \times 10^{-4} \mathrm{M} ;\) conc. \(2=\) \(4.04 \times 10^{-4} \mathrm{M}\) rate \(1=6.26 \times 10^{-5} ;\) rate \(2=6.33 \times 10^{-4}\) e. \(2 \mathrm{HI}(g) \rightarrow \mathrm{H}_{2}(g)+\mathrm{I}_{2}(g)\) HI: conc. \(1=4.18 \times 10^{-4} \mathrm{M} ;\) conc. \(2=\) \(8.36 \times 10^{-4} \mathrm{M}\) rate \(1=3.86 \times 10^{-5} ;\) rate \(2=1.54 \times 10^{-4}\)

Use the following terms to create a concept map: activation energy, alternative reaction pathway, catalysts, enzymes, and reaction rate.

What are enzymes, and what common features do they all share?

Why is it necessary to divide by the coefficient in the balanced chemical equation when calculating a reaction rate? When can that step be omitted?

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