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Chapter 17: Problem 44

Determine the oxidation number of each atom in \(\mathrm{PtCl}_{6}^{2-} .\)

Short Answer

Expert verified
The oxidation number of Pt is +4 and that of Cl is -1.

Step by step solution

01

Identify Oxidation Number of Chlorine

The oxidation number of Chlorine (Cl) in a compound is usually -1. Therefore, for the six chlorine atoms in \(\mathrm{PtCl}_{6}^{2-}\), each with an oxidation number of -1, the total oxidation number for Chlorine in this compound is -6 (6*-1).
02

Determine Oxidation Number of Pt

Next, knowing that the oxidation numbers of all atoms in a compound must add up to the overall charge on that compound, the oxidation number of Pt can be obtained. In this case, the overall charge on the compound \(\mathrm{PtCl}_{6}^{2-}\) is -2. Hence, if we let x be the oxidation number of Pt, the equation is as follows: \(x + (-6) = -2\). Simplifying this equation will give the oxidation number of Pt.
03

Solve for X

Solving the equation \(x - 6 = -2\) gives \(x = -2 + 6\), or \(x = 4\). Therefore, the oxidation number of Pt in \(\mathrm{PtCl}_{6}^{2-}\) is +4.

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