Write the balanced half-reaction for the change of \(\mathrm{O}_{2}(a q)\) to \(\mathrm{H}_{2} \mathrm{O}(l)\) in acidic solution.

Short Answer

Expert verified
The balanced half-reaction for the change of \(\mathrm{O}_{2}(a q)\) to \(\mathrm{H}_{2} \mathrm{O}(l)\) in acidic solution is: \(\mathrm{O}_{2}(a q) + 4H^{+} + 4e^{-}\) to \(2\,\mathrm{H}_{2} \mathrm{O}(l)\)

Step by step solution

01

Write Down The Unbalanced Reaction

Firstly, write down the unbalanced equation. Here, it is the reaction that represents the transformation from oxygen into water which is: \(\mathrm{O}_{2}(a q)\) to \(\mathrm{H}_{2} \mathrm{O}(l)\)
02

Balance Oxygen

Balance the oxygen atoms by adding water molecules to the side that requires more oxygen. Here, we have 2 oxygens on the left and 1 on the right. So, we add a water molecule to the right: \(\mathrm{O}_{2}(a q)\) to \(2\,\mathrm{H}_{2} \mathrm{O}(l)\)
03

Balance Hydrogen

Balance the Hydrogen atoms by adding Hydrogen ions (\( H^{+} \)) to the side that requires more Hydrogen. Here, we have 4 Hydrogen atoms on the right, and none on the left. So we add 4 Hydrogen ions on the left: \(\mathrm{O}_{2}(a q) + 4H^{+}\) to \(2\,\mathrm{H}_{2} \mathrm{O}(l)\)
04

Balance Charge

Equalize charges on both sides of the reaction by adding the required number of electrons. Since there are positive 4 charges on the left, add 4 electrons to the left side, because the electrons are negatively charged. Hence, the reaction becomes: \(\mathrm{O}_{2}(a q) + 4H^{+} + 4e^{-}\) to \(2\,\mathrm{H}_{2} \mathrm{O}(l)\)

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Key Concepts

These are the key concepts you need to understand to accurately answer the question.

Redox Reactions
Redox reactions are a fundamental type of chemical reaction that involve the transfer of electrons between species. The term 'redox' stems from two concepts: reduction and oxidation. In these reactions, oxidation refers to the loss of electrons, whereas reduction refers to the gain of electrons. The species that loses electrons is oxidized and typically acts as the reducing agent, while the species that gains electrons is reduced, acting as the oxidizing agent.

Understanding redox reactions is vitally important as they occur in various contexts, such as battery operation, cellular respiration, and many industrial processes. When we look at the change of \(\mathrm{O}_{2}(a q)\) to \(\mathrm{H}_{2} \mathrm{O}(l)\) in an acidic solution, we are witnessing a reduction process where the \(\mathrm{O}_{2}\) molecule gains electrons (and protons) to form water.
Acidic Solution Chemistry
Working with chemical reactions in acidic solutions requires an understanding of how the presence of excess hydrogen ions (\( H^{+} \)) affects the reaction. In acidic solutions, these hydrogen ions are abundant, which must be considered when balancing chemical equations, particularly redox reactions that occur in such an environment.

In the case of converting \(\mathrm{O}_{2}(a q)\) to \(\mathrm{H}_{2} \mathrm{O}(l)\), the presence of acid means we have to account for \( H^{+} \) ions when balancing the half-reaction. The acidity of the solution not only balances the hydrogen atoms in the reaction but also influences the electrical charge balance. That's why hydrogen ions are added to one side of the reaction, to adjust for both the number of atoms and the charge concurrently.
Stoichiometry
Stoichiometry is the calculation of reactants and products in chemical reactions. It is an essential concept within chemistry, allowing scientists and students alike to predict the quantities of substances consumed and produced in a given reaction. When balancing equations, especially in redox reactions, stoichiometry provides the ratios of the atoms and molecules involved, ensuring that the same number of each type of atom appears on both sides of the equation.

When balancing the half-reaction from \(\mathrm{O}_{2}(a q)\) to \(\mathrm{H}_{2} \mathrm{O}(l)\) in an acidic medium, stoichiometry is used to ensure that there's the same amount of oxygen and hydrogen atoms on both sides of the equation. Additionally, the stoichiometry of charge is considered to ensure that the total charge before and after the reaction is consistent, which is done by adding electrons to the appropriate side of the reaction.

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