The half-life of cobalt--60 is 10.47 min. How many milligrams of \(\mathrm{Co}-60\) remain after 104.7 min if you start with 10.0 \(\mathrm{mg}\) of \(\mathrm{Co}-60\) ?

Short Answer

Expert verified
Approximately 0.0098 mg of Co-60 remains after 104.7 minutes.

Step by step solution

01

Understand the half-life concept

The half-life of a substance is the time taken for half of the substance to decay. In the case of cobalt-60, its half-life is given as 10.47 minutes. This means that every 10.47 minutes, half of any existing amount of Co-60 will decay.
02

Determine the number of half-life periods

In this problem, we are asked for the amount remaining after 104.7 minutes. We need to figure out how many half-life periods this represents. We can do this by dividing the total time by the half-life. Thus, \(104.7 \, \mathrm{min} \, / \, 10.47 \, \mathrm{min/half\life} = 10 \, \mathrm{half\life\periods} \).
03

Apply the half-life decay formula

The formula for radioactive decay using half-lives is \(N = N_0 \cdot (1/2)^n \), where \(N_0\) is the initial quantity, \(N\) is the quantity remaining after \(n\) half-lives. Plugging in our values, we get: \( N = 10.0 \, \mathrm{mg} \cdot (1/2)^{10} \).
04

Calculate the remaining amount

Performing the calculation gives \( N \approx 0.0098 \, \mathrm{mg} \). Therefore, approximately 0.0098 mg of Co-60 remains after 104.7 minutes.

Unlock Step-by-Step Solutions & Ace Your Exams!

  • Full Textbook Solutions

    Get detailed explanations and key concepts

  • Unlimited Al creation

    Al flashcards, explanations, exams and more...

  • Ads-free access

    To over 500 millions flashcards

  • Money-back guarantee

    We refund you if you fail your exam.

Over 30 million students worldwide already upgrade their learning with Vaia!

Key Concepts

These are the key concepts you need to understand to accurately answer the question.

Radioactive Decay
Radioactive decay is the spontaneous process by which an unstable atomic nucleus loses energy by emitting radiation in the form of particles or electromagnetic waves. This process is random and unpredictable for any single atom; however, for a large number of atoms, statistically, it follows a predictable pattern described by the half-life of the isotope.

Radioactive decay is fundamental in nuclear physics and chemistry, and it is the underlying mechanism for various natural phenomena as well as applications ranging from medical treatments to energy generation in nuclear reactors. When studying a particular isotope, such as cobalt-60, understanding its decay helps us to predict how long it will remain active or hazardous and guides its usage in industry or medicine.

In educational contexts, to aid comprehension, we may visualize this process by comparing it to a 'timer', where each tick represents a half-life, and with each tick, the total amount of the substance is halved. This helps in grasping the concept that the material doesn't disappear all at once but rather decreases exponentially over time.
Exponential Decay
Exponential decay is a decrease in an amount at a rate proportional to the current value, leading to a decline that can be described by a mathematical function in the form of a continuously decreasing curve. In the context of half-life problems, this form of decay is significant because it quantifies how substances like radioactive isotopes diminish over time.

The mathematical representation is often expressed with the formula: \( N = N_0 \cdot (1/2)^n \) where \( N \) is the remaining quantity after \( n \) half-lives, and \( N_0 \) is the initial quantity. This function shows that after each half-life period, the substance's quantity is halved from its previous amount. For learners, visualizing the process on a graph with a steep decline initially that levels off can help convey the concept of exponential decline.

To further illustrate, if 10.0 mg of a substance had a half-life of 1 hour, after an hour there would be 5.0 mg left, after two hours 2.5 mg, and so on. In practice, this mathematical model is crucial for understanding how quickly a radioactive material becomes safe or for planning treatments in radiation therapy.
Cobalt-60
Cobalt-60 (Co-60) is a synthetic radioactive isotope of cobalt, produced by bombarding cobalt-59 with neutrons in a reactor. With a half-life of 5.27 years, Co-60 emits beta particles and gamma rays as it decays. It's a powerful source of gamma rays and is used in various applications including cancer treatment, industrial radiography, and food irradiation.

When solving problems involving Co-60, it's crucial to understand both its physical properties and the math that governs its decay. Knowing its half-life is key to determining how long it remains effective or dangerous. For instance, in the given exercise, we can calculate the remaining Co-60 after a certain period by understanding the exponential nature of its decay. This makes Co-60 an excellent example when teaching about nuclear chemistry and the practical applications of radioactive decay.

Educators often use real-world isotopes like Co-60 in exercises to provide students with an insight into how nuclear physics applies outside of the textbook, solidifying their understanding through tangible examples. It also underscores the importance of rigorous safety protocols when handling or storing radioactive materials, due to their long-term decay characteristics.

One App. One Place for Learning.

All the tools & learning materials you need for study success - in one app.

Get started for free

Study anywhere. Anytime. Across all devices.

Sign-up for free