How many milligrams remain of a 15.0 \(\mathrm{mg}\) sample of radium-226 after 6396 \(\mathrm{y} ?\) The half-life of this isotope is 1599 \(\mathrm{y}\) .

Short Answer

Expert verified
The remaining quantity of radium-226 after 6396 years is computed by evaluating \(N = N_0 * (0.5) ^ \frac{T}{T_{1/2}}\). Replace the trapped values within the formula to get the final answer.

Step by step solution

01

Identify the known quantities.

The initial quantity of radium-226 (N0) is 15.0 mg. The time that has passed (T) is 6396 years, and the half-life (T_{1/2}) is 1599 years.
02

Substitute the values into the radioactive decay formula.

Insert the known values into the decay formula to find N which represents the quantity of radium left after T years. So, \(N = 15.0 * (0.5) ^ \frac{6396}{1599}\).
03

Evaluate the expression.

Calculate the expression \(15.0 * (0.5) ^ \frac{6396}{1599}\) using a calculator to find N, the quantity of Radium-226 remaining after 6396 years.

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