Determine whether each of the following nuclear reactions involves alpha decay, beta decay, positron emission, or electron capture. \begin{equation}\begin{array}{l}{\text { a. }_{90}^{234} \mathrm{Th} \rightarrow_{-1}^{0} e+_{91}^{234} \mathrm{Pa}} \\ {\text { b. }_{92}^{238} \mathrm{U} \longrightarrow_{2}^{4} \mathrm{He}+_{90}^{234} \mathrm{Th}} \\\ {\text { c. }_{8}^{15} \mathrm{O} \longrightarrow_{+1}^{0} e+_{7}^{15} \mathrm{N}}\end{array}\end{equation}

Short Answer

Expert verified
The first reaction corresponds to beta decay, the second to alpha decay and the third to positron emission.

Step by step solution

01

Identify Decay Type a.

In the first reaction, a Th (Thorium) atom ejects an e (electron), changing into Pa (Protactinium) while atomic number increases by 1, but the mass number remains same. This is characteristic of beta decay.
02

Identify Decay Type b.

In the second reaction, a U (Uranium) atom ejects a He (Helium) atom and becomes Th (Thorium). The atomic number decreases by 2 and the mass number decreases by 4. This is characteristic of alpha decay.
03

Identify Decay Type c.

In the third reaction, an O (Oxygen) atom ejects an e (positron) and changes into N (Nitrogen). The atomic number decreases by 1. The mass number remains same. This behavior coincides with positron emission.

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