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Chapter 2: Problem 30

Write the following numbers in scientific notation. a. 0.0006730 b. 50000.0

Short Answer

Expert verified
a. \(6.73 \times 10^{-4}\) \n b. \(5 \times 10^{4}\)

Step by step solution

01

- For number less than 1

Shift the decimal point to the right until you have a number between 1 and 10. In 0.0006730, shifting the decimal point 4 places to the right gives 6.73. The number of places you shifted the decimal point is the value of the power of 10. Since the original number was less than 1, this will be a negative power. The scientific notation of 0.0006730 is therefore written as \(6.73 \times 10^{-4}\).
02

- For number greater than 1

Shift the decimal point to the left until you have a number between 1 and 10. In 50000.0, shift the decimal point 4 places to the left to get 5. The number of places you shifted the decimal point is the value of the positive power of 10. Thus, 50000.0 in scientific notation is written as \(5 \times 10^{4}\).

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Most popular questions from this chapter

You have decided to test the effects of five garden fertilizers by applying some of each to five separate rows of radishes. What is the variable you are testing? What factors should you control? How will you measure the results?

Do the following calculations, and write the answers in scientific notation. $$\begin{array}{l}{\text { a. } 37000000 \times 7100000} \\ {\text { b. } 0.000312 / 486} \\ {\text { c. } 4.6 \times 10^{4} \mathrm{cm} \times 7.5 \times 10^{3} \mathrm{cm}}\end{array}$$

Do the following calculations, and write the answers with the correct number of significant figures. $$\begin{array}{l}{\text { a. } 15.75 \mathrm{m} \times 8.45 \mathrm{m}} \\\ {\text { b. } 5650 \mathrm{L} / 27 \mathrm{min}} \\ {\text { c. } 6271 \mathrm{m} / 59.7 \mathrm{s}}\end{array}$$

Write the following measurements in long form. $$\begin{array}{l}{\text { a. } 4.5 \times 10^{3} \mathrm{g}} \\ {\text { b. } 6.05 \times 10^{-3} \mathrm{m}} \\ {\text { c. } 3.115 \times 10^{6} \mathrm{km}}\end{array}$$

Calculate the sum of 6.078 \(\mathrm{g}\) and 0.3329 \(\mathrm{g}\)
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