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Chapter 2: Problem 31

The following numbers are written in scientific notation. Write them in ordinary notation. a. \(7.050 \times 10^{-3} \mathrm{g}\) b. \(4.00005 \times 10^{7} \mathrm{mg}\)

Short Answer

Expert verified
a. 0.007050 g, b. 40000500 mg

Step by step solution

01

Solve for part A

For part A, \(7.050 \times 10^{-3}\), here the power of 10 is negative, so the decimal point needs to be moved 3 places to the left of its current position in the number 7.050. This results in the number 0.007050.
02

Solve for part B

For part B, \(4.00005 \times 10^{7}\), here the power of 10 is positive, so the decimal point needs to be moved 7 places to the right of its current position in 4.00005. Since there are not enough digits after the decimal point, zeros should be added. The result is the number 40000500.

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Most popular questions from this chapter

Calculate the sum of 6.078 \(\mathrm{g}\) and 0.3329 \(\mathrm{g}\)

Perform the following calculations, and express the answers with the correct number of significant figures. $$\begin{array}{l}{\text { a. } 2.145+0.002} \\ {\text { b. }(9.8 \times 8.934)+0.0048} \\ {\text { c. }(172.56 / 43.8)-1.825}\end{array}$$

What is the difference between a theory and a law?

What is a control? What is a variable?

Write the following measurements in long form. $$\begin{array}{l}{\text { a. } 4.5 \times 10^{3} \mathrm{g}} \\ {\text { b. } 6.05 \times 10^{-3} \mathrm{m}} \\ {\text { c. } 3.115 \times 10^{6} \mathrm{km}}\end{array}$$
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