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Chapter 5: Problem 20

Write formulas for the following ionic compounds. \begin{equation} \begin{array}{l}{\text { a. lithium sulfate }} \\ {\text { b. strontium nitrate }} \\ {\text { c. ammonium acetate }} \\ {\text { d. titanium(III) sulfate }}\end{array} \end{equation}

Short Answer

Expert verified
The formulas for the ionic compounds are: a. \(Li_2SO_4\), b. \(Sr(NO_3)_2\), c. \(NH_4C_2H_3O_2\), d. \(Ti_2(SO_4)_3\).

Step by step solution

01

Writing the formula for lithium sulfate

Referencing the periodic table, lithium is in Group 1 and thus has a +1 charge. Sulfate is a polyatomic ion with a formula of \(SO_4^{2-}\). To make the compound neutral, there must be two lithium ions for each sulfate ion, giving the formula of \(Li_2SO_4\).
02

Determining the formula for strontium nitrate

Strontium is in Group 2 and thus has a +2 charge. From the common list of polyatomic ions, the nitrate ion has a formula of \(NO_3^{-}\). To balance the charges and obtain a neutral compound, there must be two nitrate ions for each strontium ion. Therefore, the formula for strontium nitrate is \(Sr(NO_3)_2\).
03

Working out the formula for ammonium acetate

Ammonium is a polyatomic ion with a formula of \(NH_4^{+}\) and acetate is another polyatomic ion with a formula \(C_2H_3O_2^{-}\). The charges of both ions match, hence no subscript is needed. Thus, the formula will be \(NH_4C_2H_3O_2\).
04

Concluding with the formula for titanium(III) sulfate

The roman numeral III in 'titanium(III) sulfate' indicates that titanium has a +3 charge for this compound. Sulfate, as mentioned above, has a -2 charge. To balance the charges and achieve a neutral compound, the formula is \(Ti_2(SO_4)_3\).

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Most popular questions from this chapter

A number of homes have "hard water," which, as you learned in the Start-Up Activity, does not produce as many soap suds as water that contains fewer ions. Such homes often have water conditioners. Such remove the ions from the water, making it "softer" and more likely to produce soapsuds. Research how such water softeners operate by checking the Internet or by contacting a company that sells such devices. Design an experiment to test the effectiveness of the softener in removing ions from water.

Complete the table below, and then use it to answer the questions that follow. \begin{equation} \begin{array}{l}{\text { Write the formula for the following }} \\ {\text { substances: }} \\ {\text { a. manganese chloride }} \\ {\text { b. chromium(III) fluoride }} \\ {\text { c. barium oxide }}\end{array} \end{equation}

Why can't an ionic bond form between potassium and magnesium?

Write formulas for the following polyatomic ions. \begin{equation} \begin{array}{ll}{\text { a. cyanide }} & {\text { c. nitrite }} \\ {\text { b. sulfate }} & {\text { d. permanganate }}\end{array} \end{equation}

Explain how the octet rule describes how atoms form stable ions.
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