Complete the table below, and then use it to answer the questions that follow. \begin{equation} \begin{array}{l}{\text { Write the formula for the following }} \\ {\text { substances: }} \\ {\text { a. manganese chloride }} \\ {\text { b. chromium(III) fluoride }} \\ {\text { c. barium oxide }}\end{array} \end{equation}

Short Answer

Expert verified
The formulas for the compounds are: a. manganese chloride: MnCl2 b. chromium (III) fluoride: CrF3 c. barium oxide: BaO

Step by step solution

01

Identify the elements and their valences

First, let's identify the elements in each compound and their valences: a. Manganese (Mn) - valence +2, Chlorine (Cl) - valence -1 b. Chromium (Cr) - valence +3 (indicated in parenthesis), Fluoride (F) - valence -1 c. Barium (Ba) - valence +2, Oxide (O) - valence -2
02

Formulate the compounds

Next, we formulate the compounds by crossing the valences and balancing the charges: a. Manganese chloride: MnCl2 b. Chromium(III) fluoride: CrF3 c. Barium oxide: BaO
03

Verify the formulas

Finally, verify that the total positive charge from the cation matches the total negative charge from the anion. a. MnCl2: +2 from Mn matches -2 from two Cl b. CrF3: +3 from Cr matches -3 from three F c. BaO: +2 from Ba matches -2 from O

Unlock Step-by-Step Solutions & Ace Your Exams!

  • Full Textbook Solutions

    Get detailed explanations and key concepts

  • Unlimited Al creation

    Al flashcards, explanations, exams and more...

  • Ads-free access

    To over 500 millions flashcards

  • Money-back guarantee

    We refund you if you fail your exam.

Over 30 million students worldwide already upgrade their learning with Vaia!

One App. One Place for Learning.

All the tools & learning materials you need for study success - in one app.

Get started for free

Study anywhere. Anytime. Across all devices.

Sign-up for free