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Chapter 5: Problem 24

Write formulas for the following polyatomic ions. \begin{equation} \begin{array}{ll}{\text { a. cyanide }} & {\text { c. nitrite }} \\ {\text { b. sulfate }} & {\text { d. permanganate }}\end{array} \end{equation}

Short Answer

Expert verified
The formulas are: a. Cyanide: \(CN^-\), b. Sulfate: \(SO_4^{2-}\), c. Nitrite: \(NO_2^-\), and d. Permanganate: \(MnO_4^-\)

Step by step solution

01

Cyanide

The cyanide ion is made up of one Carbon atom and one Nitrogen atom, and carries a negative charge. Its chemical formula is therefore \(CN^-\)
02

Sulfate

The sulfate ion is made up of one sulfur atom and four oxygen atoms, and carries a 2-negative charge. Its chemical formula is therefore \(SO_4^{2-}\)
03

Nitrite

The nitrite ion is made up of one nitrogen atom and two oxygen atoms, and carries a negative charge. Its chemical formula is therefore \(NO_2^-\)
04

Permanganate

The permanganate ion is made up of one manganese atom and four oxygen atoms, and carries a negative charge. Its chemical formula is therefore \(MnO_4^-\)

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Most popular questions from this chapter

The electron configuration for arsenic, As, is \([\mathrm{Ar}] 3 d^{10} 4 s^{2} 4 p^{3} .\) How many valence electrons does an As atom have? Write the symbol for the ion it forms to achieve a noble-gas configuration.

Complete the table below, and then use it to answer the questions that follow. \begin{equation} \begin{array}{l}{\text { Write the formula for the following }} \\ {\text { substances: }} \\ {\text { a. manganese chloride }} \\ {\text { b. chromium(III) fluoride }} \\ {\text { c. barium oxide }}\end{array} \end{equation}

Why do most ionic compounds have such high melting and boiling points?

How is an ion different from its parent atom?

How does the octet rule help predict the chemical reactivity of an element?
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