Draw the Lewis structures for boron, nitrogen, and phosphorus.

Short Answer

Expert verified
To summarize, Boron has three unpaired electrons indicated around the symbol B, Nitrogen has a pair of electrons on two sides and one lone electron on a third side around symbol N, and Phosphorus has a similar structure to Nitrogen with a pair of electrons on two sides and one lone electron on a third side around symbol P.

Step by step solution

01

Draw the Lewis Structure for Boron

Boron has 5 electrons in its atomic structure. It uses 2 for its inner shell, then 3 remain which form the valence electrons. Indicate these three valence electrons as dots around the symbol of Boron (B).
02

Draw the Lewis Structure for Nitrogen

Nitrogen has 7 electrons in its atomic structure. It uses 2 for its inner shell, leaving 5 as the valence electrons. Indicate these five valence electrons as dots around the symbol of Nitrogen (N). The first four electrons are paired up in two sides, and then the fifth is drawn on a third side.
03

Draw the Lewis Structure for Phosphorus

Phosphorus has 15 electrons in its atomic structure. It uses 2 for its first shell and 8 for its second shell, which leaves 5 for the valence shell. Indicate these five valence electrons as dots around the symbol of Phosphorus (P). The first four electrons are paired up in two sides, and then the fifth is drawn on a third side as with Nitrogen.

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