Chapter 6: Problem 34
Draw the shapes of the following polyatomic ions. a. \(\mathrm{NH}_{4}^{+}\) b. \(\mathrm{OCl}^{-}\) c. \(\mathrm{CO}_{3}^{2-}\)
Short Answer
Expert verified
The shapes of the polyatomic ions \(\mathrm{NH}_{4}^{+}\), \(\mathrm{OCl}^{-}\), and \(\mathrm{CO}_{3}^{2-}\) are tetrahedral, bent (or V-shaped), and trigonal planar, respectively.
Step by step solution
01
Molecular Geometry of \(\mathrm{NH}_{4}^{+}\)
The molecular geometry of \(\mathrm{NH}_{4}^{+}\), where Nitrogen (N) is central atom bonded to four Hydrogen (H) atoms, is determined by considering the electron pair geometry. Nitrogen has five valence electrons, but in this ion it has given up one electron making it a positively charged cation. This leads to four bonded pairs of electrons with Hydrogen atoms and no lone pairs on Nitrogen atom. Thus, the molecular geometry of \(\mathrm{NH}_{4}^{+}\) is tetrahedral.
02
Molecular Geometry of \(\mathrm{OCl}^{-}\)
In \(\mathrm{OCl}^{-}\), where Oxygen (O) is the central atom bonded to a Chlorine (Cl) atom, Oxygen has six valence electrons. However, in this ion it gains one electron, making it a negatively charged anion, so total valence electrons become seven. The Oxygen atom forms one bond with Chlorine atom (using up two valence electrons) and with five valence electrons remaining, it forms 2.5 lone pairs. This results in 3.5 electron pairs in total, but since we cannot have a fraction of an electron pair, we just have 3 electron pairs which are one bonding pair and two lone pairs. This indicates that the molecular geometry of \(\mathrm{OCl}^{-}\) is bent or V-shaped.
03
Molecular Geometry of \(\mathrm{CO}_{3}^{2-}\)
In \(\mathrm{CO}_{3}^{2-}\), Carbon (C) is the central atom with Oxygen (O) atoms bonded to it. Carbon has four valence electrons and Oxygen has six, but this ion has two extra electrons making it a negatively charged anion. The total number of valence electrons is 4 + 3*6 +2 = 24. Each Carbon-Oxygen bond uses up two electrons, and there are three of them, using up 6 electrons. The 18 remaining electrons are distributed as lone pairs on the Oxygen atoms with each Oxygen having 3 lone pairs. Therefore, the molecular geometry of \(\mathrm{CO}_{3}^{2-}\) is trigonal planar as there are three bonding pairs and no lone pair on the central Carbon atom.
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Key Concepts
These are the key concepts you need to understand to accurately answer the question.
Polyatomic Ions
Polyatomic ions are charged entities consisting of two or more atoms covalently bonded together, or of a metal complex that acts as a single unit in chemical reactions. These ions can carry either a positive charge, known as a cation, as in the case of
For example, the geometry of
NH_{4}^{+}
, or a negative charge, called an anion, like OCl^{-}
and CO_{3}^{2-}
. Understanding the structure of polyatomic ions is crucial, as it affects the physical and chemical properties of ionic compounds they form.For example, the geometry of
NH_{4}^{+}
is tetrahedral as a result of its four bonded pairs of electrons which will repel each other to positions that minimize repulsion, hence creating a three-dimensional shape. Similarly, for OCl^{-}
and CO_{3}^{2-}
, the electron distribution around the central atom determines their bent and trigonal planar shapes, respectively.- Ammonium (
NH_{4}^{+}
): A common cation in organic and inorganic chemistry. - Hypochlorite (
OCl^{-}
): A chlorine oxyanion and the conjugate base of hypochlorous acid. - Carbonate (
CO_{3}^{2-}
): An anion found in many salts and minerals, crucial for biological systems and geological formations.
Valence Electrons
Valence electrons play a pivotal role in chemical bonding, as they are the outermost electrons of an atom and thus available for forming bonds with other atoms. These electrons determine the bonding capacity, or valency, of an atom and influence the resulting molecular geometry.
Counting Valence Electrons
For polyatomic ions likeNH_{4}^{+}
, OCl^{-}
, and CO_{3}^{2-}
, it is important to consider both the valence electrons of the constituent atoms and the overall charge of the ion when determining the total number of valence electrons. For instance, the ammonium ion (NH_{4}^{+}
) has one less valence electron than the neutral nitrogen atom due to its positive charge. Similarly, oxygen in hypochlorite (OCl^{-}
) gains an additional electron, resulting in a negative charge. Carbonate ion (CO_{3}^{2-}
) has two extra electrons because of its -2 charge. These adjustments are crucial in predicting the molecular shapes of these ions via the VSEPR theory (Valence Shell Electron Pair Repulsion theory). Electron Pair Geometry
Electron pair geometry, determined by the arrangement of electron pairs around a central atom, is a key concept in understanding the shape of molecules and polyatomic ions. According to the VSEPR theory, electron pairs will arrange themselves as far apart as possible to minimize electron pair repulsion. In the case of
For example, oxygen in hypochlorite has one bond pair and two lone pairs, which arrange themselves in a trigonal planar electron pair geometry, but the molecular shape observed is bent due to the repulsion between the lone pairs. In carbonate ion, the three bond pairs around the central carbon atom result in a trigonal planar electron pair geometry as well as molecular geometry, as there are no lone pairs to alter the shape.
NH_{4}^{+}
, the four bonds around nitrogen define a tetrahedral electron pair geometry. However, for ions like OCl^{-}
, with bond pairs and lone pairs, the geometry must account for both types of electron pairs.For example, oxygen in hypochlorite has one bond pair and two lone pairs, which arrange themselves in a trigonal planar electron pair geometry, but the molecular shape observed is bent due to the repulsion between the lone pairs. In carbonate ion, the three bond pairs around the central carbon atom result in a trigonal planar electron pair geometry as well as molecular geometry, as there are no lone pairs to alter the shape.