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Chapter 7: Problem 26

How many moles of sodium ions are there in a sample of salt water that contains \(4.11 \times 10^{22} \mathrm{Na}^{+}\) ions?

Short Answer

Expert verified
The amount of moles of Sodium ions in the sample is approximately 0.682 moles.

Step by step solution

01

Understanding the Question and What is Given

In this problem, we know the number of Sodium ions (\(Na^{+}\)), which is \(4.11 \times 10^{22}\). The question is asking for the number of moles of the Sodium ions.
02

Convert Number of Ions into Moles

First, we need to recall Avogadro's number: \(6.022 \times 10^{23}\) entities (ions in our case) per mole. We can use this information to convert the number of Sodium ions into moles. The conversion factor will be (1 mole / \(6.022 \times 10^{23}\) Na ions).
03

Calculate the Amount

We will multiply the given number of Sodium ions, \(4.11 \times 10^{22}\), by the conversion factor (1 mole / \(6.022 \times 10^{23}\) Na ions), so we can solve for the number of moles. Following the operation: \((4.11 \times 10^{22} Na^{+} ions) \times (1 mole / 6.022 \times 10^{23} Na^{+} ions)\), we find the moles of Sodium ions.

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Most popular questions from this chapter

How many grams are in each of the following samples? a. 1.000 mol \(\mathrm{NaCl}\) (molar mass of \(\mathrm{NaCl}=\) 58.44 \(\mathrm{g} / \mathrm{mol} )\) b. 2.000 \(\mathrm{mol} \mathrm{H}_{2} \mathrm{O}\) (molar mass of \(\mathrm{H}_{2} \mathrm{O}=\) 18.02 \(\mathrm{g} / \mathrm{mol} )\) c. 3.5 \(\mathrm{mol} \mathrm{Ca}(\mathrm{OH})_{2}\) (molar mass of \(\mathrm{Ca}(\mathrm{OH})_{2}=74.10 \mathrm{g} / \mathrm{mol} )\)

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