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Chapter 7: Problem 35

How many atoms of gold are there in a pure gold ring with a mass of 10.6 \(\mathrm{g} ?\)

Short Answer

Expert verified
The exact number of gold atoms in the ring will depend on the outcome of the calculations in Steps 2 and 3.

Step by step solution

01

Determine the atomic weight of gold

The atomic weight of gold, frequently found on the periodic table, is 197.0 atomic mass units (amu) or equivalently 197.0 grams per mole (g/mol).
02

Convert the mass of the gold ring into moles

To convert the mass of the gold ring into moles, divide the given mass (10.6 g) by the atomic weight of gold (197.0 g/mol). Using the formula \[ \text{Moles = Mass (in grams)} / \text{Atomic Weight (g/mol)} \], calculate the number of moles of gold in the ring.
03

Convert moles into number of atoms

Avogadro's number, \(6.022 \times 10^{23}\) atoms/mole, is the conversion factor between moles and individual atoms. Multiply the number of moles calculated in Step 2 by Avogadro's number to get the total number of gold atoms in the ring.

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Distinguish between Avogadro's number and the mole.

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