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Chapter 7: Problem 36

How many formula units are there in 302.48 g of zinc chloride, \(\mathrm{ZnCl}_{2} ?\) The molar mass of zinc chloride is 136.29 \(\mathrm{g} / \mathrm{mol} .\)

Short Answer

Expert verified
There are approximately \(1.34 \times 10^{24}\) formula units in 302.48 g of zinc chloride.

Step by step solution

01

Determination of moles

First, calculate the number of moles of zinc chloride using the formula: moles = mass / molar mass. Substituting the given values, we get: moles = 302.48 g / 136.29 g/mol = 2.22 mol.
02

Conversion to formula units

The number of formula units is determined by multiplying the number of moles by Avogadro's number (6.02 x 10^23). So, formula units = moles x Avogadro's number = 2.22 mol x 6.02 x 10^23 = 1.34 x 10^24.
03

Final Answer

Hence, there are 1.34 x 10^24 formula units in 302.48 g of zinc chloride.

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