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Chapter 7: Problem 41

How many moles of propane are in a pressure container that has 2.55 kg of propane, \(\mathrm{C}_{3} \mathrm{H}_{8}\left(\) molar mass of \(\mathrm{C}_{3} \mathrm{H}_{8}=44.11 \mathrm{g} / \mathrm{mol}\right) ?\)

Short Answer

Expert verified
There are approximately \(57.79 \, \mathrm{mol}\) of propane in the pressure container.

Step by step solution

01

Convert mass from kilograms to grams

Since we know 1 kg is equal to 1,000 g, we multiply the given mass in kg by 1000 to get the mass in grams. Therefore, the mass in grams of the propane is \(2.55 \, \mathrm{kg} * 1,000 = 2550 \, \mathrm{g}\)
02

Calculate the number of moles

Using the formula for calculating the number of moles (n), where n = mass/molar mass, with the mass in grams(i.e., 2550 g) and the molar mass of propane (\(44.11 \, \mathrm{g}/\mathrm{mol}\)), we calculate the number of moles as follows: \(n = 2550 \, \mathrm{g} / 44.11 \, \mathrm{g}/\mathrm{mol} = 57.79 \, \mathrm{mol}\)
03

Round off to two decimal places

Standard scientific notation often involves rounding off to two decimal places where necessary. Therefore, the number of moles of propane \(57.79 \, \mathrm{mol}\) is rounded off to \(57.79 \, \mathrm{mol}\)

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