How would you determine the number of molecules in 3 mol of oxygen, \(\mathrm{O}_{2} ?\)

Short Answer

Expert verified
There are \(1.807 \times 10^{24}\) \(\mathrm{O}_{2}\) molecules in 3 moles of oxygen.

Step by step solution

01

Understanding Avogadro's number

Avogadro's number is a constant, \(6.022 \times 10^{23}\), which signifies the number of entities in one mole of a substance.
02

Multiply the number of moles by Avogadro's number

The problem states that we have 3 moles of \(\mathrm{O}_{2}\). According to Avogadro, 1 mole of any substance contains \(6.022 \times 10^{23}\) entities of it. Thus, to find the number of entities (molecules in this case) in 3 moles of \(\mathrm{O}_{2}\), you multiply 3 by Avogadro's number.

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Key Concepts

These are the key concepts you need to understand to accurately answer the question.

Mole Concept
The 'mole' is a fundamental concept in chemistry that serves as a bridge between the microscopic world of atoms and molecules and the macroscopic world we can measure. At its core, a mole is simply a unit of measurement used in chemistry, similar to using 'dozen' for counting eggs.

In more technical terms, one mole represents Avogadro's number of entities, which is roughly equal to 6.022 x 1023. This massive number, known as Avogadro's constant, was chosen so that the mass of one mole of a substance in grams is approximately equal to its average atomic or formula mass. Therefore, if you have one mole of water, you have 6.022 x 1023 water molecules, which would weigh about 18 grams because the molar mass of water is roughly 18 g/mol.

A common analogy is to think of the mole as a 'chemical dozen'. Just like one dozen always refers to 12 items, one mole always refers to 6.022 x 1023 particles, whether they are atoms, ions, molecules, or other particles.
Chemical Substance Quantification
Quantifying chemical substances accurately is crucial in chemistry for performing various types of calculations, from determining how much product will form in a reaction to analyzing the composition of a substance. Chemists use the mole concept as a standard unit for this quantification because it allows for easy translation between atoms on the microscopic scale and grams on the macroscopic scale.

When dealing with chemical substances, it is important to know not only the number of entities but also their mass. This is where the concept of molar mass comes in. The molar mass is the weight of one mole of a given substance and is usually expressed in grams per mole (g/mol). It is numerically equivalent to the substance's atomic or molecular weight but scaled up by Avogadro's number to reflect the weight of one mole of entities as opposed to just one entity.

For example, when quantifying substances like oxygen gas (O_2), the molar mass of oxygen is 16 g/mol. However, since oxygen gas naturally exists as diatomic molecules (O_2), the molar mass is 32 g/mol. Knowing the molar mass and the quantity in moles allows chemists to convert between mass in grams and the number of entities, making chemical quantification a seamless process.
Stoichiometry
Stoichiometry is the field of chemistry that involves the calculation of the relative quantities of reactants and products in chemical reactions. It is rooted deeply in the conservation of mass and the mole concept, allowing chemists to predict how much product will result from a given quantity of reactants and vice versa.

In stoichiometric calculations, the coefficients of a balanced chemical equation tell the ratio of moles of each substance participating in the reaction. By using these ratios, one can determine how many moles of a substance will react or form. For instance, if a reaction states that 2 moles of hydrogen (H_2) react with 1 mole of oxygen (O_2) to form water, and you start with 3 moles of oxygen, you can predict that 6 moles of hydrogen will be needed and that 6 moles of water will be produced, according to the balanced equation.

Understanding stoichiometry is vital for a chemist, as it enables accurate design of experiments, ensures that reactions proceed to completion under the desired conditions, and helps in determining the optimum yield of products.

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