Calculating the Molar Mass of a Compound The graphing calculator can run a program that calculates the molar mass of a compound given the chemical formula for the compound. This program will prompt for the number of elements in the formula, the number of atoms of each element in the formula, and the atomic mass of each element in the formula. It then can be used to find the molar masses of various compounds. Go to Appendix \(C\) . If you are using a TI-83 Plus, you can download the program MOLMASS and data sets and run the application as directed. If you are using another calculator, your teacher will provide you with the keystrokes and data sets to use. After you have graphed the data, answer the questions below. a. What is the molar mass of \(\mathrm{BaTiO}_{3} ?\) b. What is the molar mass of \(\mathrm{PbCl}_{2} ?\) c. What is the molar mass of \(\mathrm{NH}_{4} \mathrm{NO}_{3} ?\)

Step by step solution

01

Identify the formula elements and their atomic masses

The formulas given are \(\mathrm{BaTiO}_{3}, \mathrm{PbCl}_{2}, \) and \(\mathrm{NH}_{4} \mathrm{NO}_{3}\). So, the first things to identify are the elements present in these formulas and their atomic masses. For \(\mathrm{BaTiO}_{3}\), the elements are Ba (Barium), Ti (Titanium), and O (Oxygen) with atomic masses approximately 137.33, 47.87, and 16.00 respectively. For \(\mathrm{PbCl}_{2}\), the elements are Pb (Lead) and Cl (Chlorine), with atomic masses approximately 207.2 and 35.45 respectively. For \(\mathrm{NH}_{4} \mathrm{NO}_{3}\), the elements are N (Nitrogen), H (Hydrogen), and O (Oxygen), with atomic masses approximately 14.01, 1.01, and 16.00 respectively.

02

Calculate the molar mass of each compound

For each compound, calculate the molar mass by multiplying the atomic mass of each element by the number of atoms of that element in the compound, and then sum these values. For \(\mathrm{BaTiO}_{3}\), the molar mass is \(137.33 + 47.87 + 3(16.00) = 233.20\) g/mol. For \(\mathrm{PbCl}_{2}\), the molar mass is \(207.2 + 2(35.45) = 278.10\) g/mol. For \(\mathrm{NH}_{4} \mathrm{NO}_{3}\), the molar mass is \(2(14.01) + 4(1.01) + 3(16) = 80.05\) g/mol.

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