What must form in order for a double-displacement reaction to occur?

Short Answer

Expert verified
A double-displacement reaction occurs when there's formation of an insoluble solid (precipitate), formation of water (in a neutralization reaction), or formation of a gas.

Step by step solution

01

Definition of Double-Displacement Reaction

A double-displacement reaction, also known as a metathesis reaction, is a type of chemical reaction where two compounds react, and the positive ions (cation) and the negative ions (anion) of the two reactants switch places, forming two new compounds.
02

Basic Conditions for Occurrence

For a double-displacement reaction to occur, one of the following conditions must be met: formation of an insoluble solid (precipitation reaction), formation of water (neutralization reaction), or formation of a gas. These products must be more stable than the reactants.
03

Explanation of Conditions

In a precipitation reaction, an insoluble solid (precipitate) forms from two ionic compounds in solution. In a neutralization reaction, a base and an acid react to form water and a salt. In the third condition, two reactants combine to form a gas that escapes from the solution.

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Key Concepts

These are the key concepts you need to understand to accurately answer the question.

Metathesis Reaction
A metathesis or double-displacement reaction is fundamental in the study of chemistry. It involves the exchange of partners between two reacting chemical compounds. Imagine it as a dance between two couples where partners swap to form new pairs. To put it into chemical language, during a metathesis reaction, the cations (positively charged ions) and the anions (negatively charged ions) of two different molecules exchange places.

This results in two new compounds and often occurs in aqueous solutions where the reactants are dissolved in water. For students to visualize this process, think of the general format: \( AB + CD \rightarrow AD + CB \). The letters A and C represent the cations, while B and D symbolize the anions. Through this reaction, compounds with new properties emerge, demonstrating the dynamic nature of chemistry.
Precipitation Reaction
Precipitation reactions are a specific type of double-displacement reaction where an insoluble solid, called a precipitate, forms as a result of the reaction. For a substance to be deemed 'insoluble,' it does not dissolve well in a particular solvent, usually water.

Here is a typical scenario: when two clear solutions containing soluble salts are mixed, a cloudy or solid mass appears abruptly. That's your precipitate. This process is like a sudden rain shower on a clear day, hence the term 'precipitation'. For students performing lab experiments, it's important to understand that not all ionic compounds react to form a precipitate. Thus, knowledge of solubility rules is crucial. These rules can predict whether certain combinations of ions will result in a precipitate and significantly aid in understanding the outcome of chemical reactions.
Neutralization Reaction
A neutralization reaction is a special kind of double-displacement reaction that occurs when an acid and a base react together. The name 'neutralization' is used because the acid and base properties neutralize each other.

The most common example of such a reaction is the formation of water (H2O) and a salt when an acid (which has at least one H⁺ ion) and a base (which has at least one OH⁻ ion) are mixed. The general equation for neutralization is: \( HA + BOH \rightarrow BA + H_2O \). 'HA' represents the acid, 'BOH' is the base, and 'BA' is the resulting salt. This type of reaction is exothermic, meaning it releases heat. It's this reaction that neutralizes the pH level of a solution. Understanding neutralization reactions is not only critical for solving chemistry problems but also has practical applications such as antacid tablets relieving stomach acidity.

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Most popular questions from this chapter

How does the process of balancing an equation illustrate the law of conservation of mass?

Predict the products for each of the following reactions. Write a total ionic equation and a net ionic equation for each reaction. If no reaction occurs, write "no reaction." $$\begin{array}{l}{\text { a. } \mathrm{Li}_{2} \mathrm{CO}_{3}(a q)+\mathrm{BaBr}_{2}(a q) \longrightarrow} \\ {\text { b. } \mathrm{Na}_{2} \mathrm{SO}_{4}(a q)+\mathrm{Sr}\left(\mathrm{NO}_{3}\right)_{2}(a q) \rightarrow} \\ {\text { c. } \mathrm{Al}(s)+\mathrm{NiCl}_{2}(a q) \rightarrow} \\ {\text { d. } \mathrm{K}_{2} \mathrm{CO}_{3}(a q)+\mathrm{FeCl}_{3}(a q) \rightarrow}\end{array}$$

How should each of the following substances be represented in a total ionic equation? $$\begin{array}{l}{\text { a. } \mathrm{KCl}(a q)} \\ {\text { b. } \mathrm{H}_{2} \mathrm{O}(l)} \\ {\text { c. } \mathrm{Cu}\left(\mathrm{NO}_{3}\right)_{2}(a q)} \\ {\text { d. } \mathrm{AgCl}(s)}\end{array}$$

Identify the type of reaction for each of the following. Then, predict products for the reaction, and balance the equation." reaction occurs, write "no reaction." $$\text{a}. \mathrm{HCl}(a q)+\mathrm{NaOH}(a q) \rightarrow\mathrm{NaCl}(a q)+\mathrm{H}_{2} \mathrm{O}(l)$$ $$\text{b}. \mathrm{Mg}(s)+2 \mathrm{HCl}(a q) \rightarrow \mathrm{MgCl}_{2}(a q)+\mathrm{H}_{2}(g)$$ $$\text{c}. \mathrm{CdCl}_{2}(a q)+\mathrm{Na}_{2} \mathrm{CO}_{3}(a q) \rightarrow 2 \mathrm{NaCl}(a q)+\mathrm{CdCO}_{3}(s)$$

Write a balanced equation for each of the following: $$\begin{array}{c}{\text { a. copper(II) sulfate }+\text { ammonium sulfide } \rightarrow} \\ {\text { copper(II) sulfide + ammonium sulfate }} \\ {\text { b. nitric acid + barium hydroxide } \rightarrow} \\ {\text { water + barium nitrate }}\end{array}$$ $$ \begin{array}{c}{\text { c. barium chloride + phosphoric acid } \rightarrow} \\\ {\text { barium phosphate + hydrochloric acid }}\end{array} $$

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