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Chapter 8: Problem 27

Write a balanced equation for each of the following: a. iron(III) oxide + magnesium \(\rightarrow\) magnesium oxide + iron b. nitrogen dioxide + water \(\longrightarrow\) nitric acid + nitrogen monoxide c. silicon tetrachloride + water \(\rightarrow\) silicon dioxide + hydrochloric acid

Short Answer

Expert verified
The balanced equations are: a. \( Fe_2O_3 + 3Mg \rightarrow 3MgO + 2Fe \) b. \( 3NO_2 + H_2O \rightarrow 2HNO_3 + NO \) c. \( SiCl_4 + 2H_2O \rightarrow SiO_2 + 4HCl \)

Step by step solution

01

Write down the unbalanced equations

Write down the unbalanced equations. For reaction a, the unbalanced equation is \( Fe_2O_3 + Mg \rightarrow MgO + Fe \). For reaction b, the unbalanced equation is \( NO_2 + H_2O \rightarrow HNO_3 + NO \). For reaction c, the unbalanced equation is \( SiCl_4 + H_2O \rightarrow SiO_2 + HCl \)
02

Balance the Iron Atoms

To balance the iron (Fe) atoms in reaction a, there are 2 atoms in the reactants side (in \( Fe_2O_3 \)) and 1 in the products side. To balance, it is necessary to adjust the stoichiometric coefficient for Fe in the products side to 2. The intermediate equation becomes \( Fe_2O_3 + Mg \rightarrow MgO + 2Fe \)
03

Balance the Magnesium Atoms

The magnesium atom (Mg) appears in one molecule on each side. Thus the equation \( Fe_2O_3 + Mg \rightarrow MgO + 2Fe \) is balanced for Mg.
04

Balance the Oxygen Atoms

For oxygen, the reactants side has 3 atoms (in \( Fe_2O_3 \)) while the products side has 1 (in \( MgO \)). To balance, it is necessary to adjust the stoichiometric coefficient for \( MgO \) in the products side to 3. The final balanced equation for reaction a is \( Fe_2O_3 + 3Mg \rightarrow 3MgO + 2Fe \)
05

Balance the Atoms for Reactions b and c

Using the same process, balance the equations for reactions b and c. The final equations are respectively \( 3NO_2 + H_2O \rightarrow 2HNO_3 + NO \) and \( SiCl_4 + 2H_2O \rightarrow SiO_2 + 4HCl \)

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Write a balanced equation for each of the following: $$ \begin{array}{r}{\text { a. propanol }\left(\mathrm{C}_{3} \mathrm{H}_{7} \mathrm{OH}\right)+\text { oxygen } \longrightarrow} \\ {\text { carbon dioxide }+\text { water }}\\\\{\text { b. aluminum }+\text { iron ( II) nitrate } \longrightarrow} \\ {\text { aluminum nitrate + iron }}\\\\{\text { c. lead(IV) oxide } \longrightarrow} {\text { lead(II) oxide + oxygen }}\end{array} $$

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