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Chapter 8: Problem 29

Write a balanced equation for each of the following: $$ \begin{array}{r}{\text { a. propanol }\left(\mathrm{C}_{3} \mathrm{H}_{7} \mathrm{OH}\right)+\text { oxygen } \longrightarrow} \\ {\text { carbon dioxide }+\text { water }}\\\\{\text { b. aluminum }+\text { iron ( II) nitrate } \longrightarrow} \\ {\text { aluminum nitrate + iron }}\\\\{\text { c. lead(IV) oxide } \longrightarrow} {\text { lead(II) oxide + oxygen }}\end{array} $$

Short Answer

Expert verified
The balanced equations for the chemical reactions given are a) \(C_{3}H_{7}OH + 5O_{2} \longrightarrow 3CO_{2} + 4H_{2}O\), b) \(2Al + 3Fe(NO_{3})_{2} \longrightarrow 2Al(NO_{3})_{3} + 3Fe\), and c) \(2PbO_{2} \longrightarrow 2PbO + O_{2}\)

Step by step solution

01

Balancing equation for reaction a

Write the unbalanced equation first: \(\mathrm{C}_{3} \mathrm{H}_{7} \mathrm{OH}+\mathrm{O}_{2} \longrightarrow \mathrm{CO}_{2}+\mathrm{H}_{2}\mathrm{O}\). After which balance the carbons followed by the hydrogens and finally the oxygens. The balanced equation then becomes: \(\mathrm{C}_{3} \mathrm{H}_{7} \mathrm{OH}+5\mathrm{O}_{2} \longrightarrow 3\mathrm{CO}_{2}+4\mathrm{H}_{2}\mathrm{O}\)
02

Balancing equation for reaction b

Write the unbalanced equation: \(Al+Fe(NO_{3})_{2} \longrightarrow Al(NO_{3})_{3}+Fe\). Start by balancing the aluminum and then the iron followed by nitrate ions. The final balanced equation becomes: \(2Al+3Fe(NO_{3})_{2} \longrightarrow 2Al(NO_{3})_{3}+3Fe\)
03

Balancing equation for reaction c

First write the unbalanced equation: \(PbO_{2} \longrightarrow PbO+O_{2}\). Begin by balancing the lead atoms followed by the oxygen atoms resulting in the balanced equation: \(2PbO_{2} \longrightarrow 2PbO+O_{2}\)

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Most popular questions from this chapter

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