Predict the products for each of the following reactions. Write a total ionic equation and a net ionic equation for each reaction. If no reaction occurs, write "no reaction." $$\begin{array}{l}{\text { a. } \mathrm{Li}_{2} \mathrm{CO}_{3}(a q)+\mathrm{BaBr}_{2}(a q) \longrightarrow} \\ {\text { b. } \mathrm{Na}_{2} \mathrm{SO}_{4}(a q)+\mathrm{Sr}\left(\mathrm{NO}_{3}\right)_{2}(a q) \rightarrow} \\ {\text { c. } \mathrm{Al}(s)+\mathrm{NiCl}_{2}(a q) \rightarrow} \\ {\text { d. } \mathrm{K}_{2} \mathrm{CO}_{3}(a q)+\mathrm{FeCl}_{3}(a q) \rightarrow}\end{array}$$

Short Answer

Expert verified
a. Ba2+ + CO3 2- => BaCO3 (s), Reaction occurs \n b. Sr2+ + SO4 2- => SrSO4 (s), Reaction occurs \n c. Al (s) + 2Ni2+ => 2Al3+ + Ni, Reaction occurs \n d. Fe3+ + CO3 2- => Fe2(CO3)3 (s), Reaction occurs

Step by step solution

01

- Predicting the products

You use the concept of double displacement reaction for equations a, b, and d (A+B- + C+D- => A+D- +C+B-). For equation c, you use the concept of redox reaction, wherein the transfer of electrons from one substance to another happens.\n a. Li2CO3 + BaBr2 => LiBr + BaCO3 \n b. Na2SO4 + Sr(NO3)2 => NaNO3 + SrSO4 \n c. Al + NiCl2 => AlCl3 + Ni \n d. K2CO3 + FeCl3 => KCl + Fe2(CO3)3
02

- Writing the total ionic equation

The total ionic equation represents all particles in the solution as ions. If any compound is insoluble, it will not break into ions.\n a. 2Li+ + CO3 2- + Ba2+ + 2Br- => 2Li+ + 2Br- + BaCO3 (s) \n b. 2Na+ + SO4 2- + Sr2+ + 2NO3- => 2Na+ + 2NO3- + SrSO4 (s) \n c. Al (s) + Ni2+ + 2Cl- => 2Al3+ + 6Cl- + Ni (s) \n d. 2K+ + CO3 2- + Fe3+ + 3Cl- => 2K+ + 3Cl- + Fe2(CO3)3 (s)
03

- Writing the net ionic equation

The net ionic equation eliminates spectator ions (ions that don't change during the reaction).\n a. Ba2+ + CO3 2- => BaCO3 (s) \n b. Sr2+ + SO4 2- => SrSO4 (s) \n c. Al (s) + 2Ni2+ => 2Al3+ + Ni \n d. Fe3+ + CO3 2- => Fe2(CO3)3 (s)
04

- Determining if a reaction occurs

A reaction occurs if a precipitate, gas or water forms. If not, 'no reaction' is written. BaCO3, SrSO4, and Fe2(CO3)3 are insoluble compounds so they form precipitates. In equation c, Al reacts with NiCl2. Thus there's a reaction in all equations.

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