Create an activity series for the hypothetical elements \(\mathrm{A}, \mathrm{J}, \mathrm{Q},\) and \(\mathrm{Z}\) by using the reaction information provided below. $$\begin{array}{c}{\mathrm{A}+\mathrm{ZX} \rightarrow \mathrm{AX}+\mathrm{Z}} \\\ {\mathrm{J}+\mathrm{ZX} \rightarrow \text { no reaction }} \\\ {\mathrm{Q}+\mathrm{AX} \rightarrow \mathrm{QX}+\mathrm{A}}\end{array}$$

Short Answer

Expert verified
The activity series for the given elements is: Q, A, Z, J

Step by step solution

01

Identify the Reactions

First, analyze the given reactions to understand which elements are replacing others. In the first reaction \(A+ZX \rightarrow AX+Z\), A replaces Z in compound ZX. In the second reaction \(J+ZX \rightarrow\) no reaction, J isn't able to displace Z, indicating J is less reactive than Z. Lastly, in the reaction \(Q+AX \rightarrow QX+A\), Q replaces A, implying Q is more active than A.
02

Order the Elements

By using the information gathered from observing the reactions, arrange the elements in order of reactivity. Based on the reactions, Q displaces A, and A displaces Z, but J couldn’t displace Z. This implies Q is the most reactive, followed by A, then Z, and, lastly J which failed to instigate a reaction.
03

Create the Activity Series

Now, write the activity series for the given elements based on their reactivity. The list should start with the most active element and end with the least active one. So, Q is most reactive, followed by A, then Z and finally J is the least reactive element.

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