Chapter 5: Problem 36
a. Which of the following cations is least likely to form: \(\mathrm{Sr}^{2+}, \mathrm{Al}^{3+}, \mathrm{K}^{2+} ?\) b. Which of the following anions is least likely to form: \(\mathrm{I}^{-}, \mathrm{Cl}^{-}, \mathrm{O}^{2-?}\) ?
Short Answer
Expert verified
a. \(\text{K}^{2+} \), b. \(\text{O}^{2-} \)
Step by step solution
01
Examine the Formation of Cations
Identify and examine the cations: \(\text{Sr}^{2+} \), \(\text{Al}^{3+} \), \(\text{K}^{2+} \). Strontium (Sr) and Aluminum (Al) commonly form \(\text{Sr}^{2+} \) and \(\text{Al}^{3+} \) ions respectively due to their positions in the periodic table and their stable configurations upon losing the noted electrons.
02
Analyze Potassium's Stable Ion
Potassium (K) typically forms \(\text{K}^+ \) by losing one electron to achieve a noble gas configuration. Forming \(\text{K}^{2+} \) by losing two electrons is highly unlikely, as it would disrupt a stable electronic configuration and require substantially more energy.
03
Identify the Least Likely Cation
Given their tendencies, \(\text{K}^{2+} \) is the least likely to form because Potassium prefers to form \(\text{K}^+ \) for a stable electron arrangement.
04
Examine the Formation of Anions
Identify and examine the anions: \(\text{I}^- \), \(\text{Cl}^- \), \(\text{O}^{2-} \). Iodine (I) and Chlorine (Cl) commonly form \(\text{I}^- \) and \(\text{Cl}^- \) ions respectively by gaining one electron to achieve stable noble gas configurations.
05
Analyze Oxygen's Stable Ion
Oxygen (O) typically forms \(\text{O}^{2-} \) by gaining two electrons to achieve a noble gas configuration.
06
Identify the Least Likely Anion
Given their tendencies, \(\text{Cl}^- \) and \(\text{I}^- \) are more probable, while \(\text{O}^{2-} \) is less probable compared to the one-electron gain anions.
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Key Concepts
These are the key concepts you need to understand to accurately answer the question.
Formation and Characteristics of Cations
Cations are positively charged ions that form when an atom loses one or more electrons. This loss results in a greater number of protons than electrons. The process of forming cations is typically tied to an element's desire to achieve a stable electron configuration, often mirroring the closest noble gas.
For instance:
For instance:
- Strontium (Sr) loses two electrons to form \(\text{Sr}^{2+}\), resembling the electron configuration of xenon (Xe).
- Aluminum (Al) loses three electrons to form \(\text{Al}^{3+}\), achieving a stable configuration similar to neon (Ne).
- Potassium (K) primarily loses one electron to form \(\text{K}^+\), mimicking the electron structure of argon (Ar).
Formation and Characteristics of Anions
Anions are negatively charged ions created when an atom gains one or more electrons. This gain leads to a greater number of electrons than protons. Much like cations, the formation of anions is driven by the pursuit of a stable electron configuration, often resembling that of a noble gas.
For example:
For example:
- Iodine (I) commonly gains one electron to form \(\text{I}^-\), giving it a configuration like xenon (Xe).
- Chlorine (Cl) also gains one electron to form \(\text{Cl}^-\), achieving an electron arrangement similar to argon (Ar).
- Oxygen (O) typically gains two electrons to form \(\text{O}^{2-}\), aligning its configuration with neon (Ne).
Understanding Electron Configuration
Electron configuration describes the distribution of electrons in an atom’s orbitals. It plays a key role in determining how an atom will interact with other atoms, including its propensity to form cations or anions.
Atoms aim to accomplish the electron configuration of the nearest noble gas, as achieving such a state signifies maximum stability. This often means:
Atoms aim to accomplish the electron configuration of the nearest noble gas, as achieving such a state signifies maximum stability. This often means:
- Losing electrons to form cations when fewer electrons are needed to reach stability.
- Gaining electrons to form anions when more energy is released by acquiring electrons.