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Chapter 1: Problem 11

IUPAC name of the compound is (a) 4 -Ethyl-3-methyl hex-1-en-2-ol (b) 3 -Ethyl-4-methyl hex- 5 -en- 2 -ol (c) 3-Methyl-4-ethyl hex-1-en-2-ol (d) 3-Ethyl-4-methyl-2-hydroxy hex-5-ene.

Short Answer

Expert verified
Answer: 3-Ethyl-4-methyl hex-5-en-2-ol

Step by step solution

01

Identify the carbon chain

Locate the longest continuous carbon chain in the compound. In this case, it is a hexane, since the longest chain consists of six carbon atoms.
02

Identify the substituents and their positions

Check for any substituents branching out from the main chain. Since we are given their positions in the options, we can infer the following: (a) 4 -Ethyl-3-methyl hex-1-en-2-ol (b) 3 -Ethyl-4-methyl hex- 5 -en- 2 -ol (c) 3-Methyl-4-ethyl hex-1-en-2-ol (d) 3-Ethyl-4-methyl-2-hydroxy hex-5-ene
03

Determine the correct position and numbering of carbon atoms

Using the lowest number rule (also known as the first point of difference rule), try numbering the carbon atoms of the main chain from left to right and from right to left, then choose the appropriate side that provides the lowest overall numbering to substituent positions. Comparing the options, we can see that option (b) has the appropriate numbering; therefore, it is the correct IUPAC name for the given compound: Correct IUPAC name: 3-Ethyl-4-methyl hex-5-en-2-ol

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Most popular questions from this chapter

The boiling point of \(\mathrm{CH} 3 \mathrm{OH}\) is \(65^{\circ} \mathrm{C}\), while the boiling point of \(\mathrm{CH} 3 \mathrm{SH}\) is only \(6^{\circ} \mathrm{C}\). Explain this difference in boiling point.

The most stable free radical among the following is (a) C=CC(C)C (b) c1ccccc1 (c) \(\left(\mathrm{CH}_{3}\right)_{3} \mathrm{C}\) (d) \(\mathrm{CH}_{2}=\mathrm{CH}-\mathrm{CH}_{2}-\mathrm{CH}_{2}\).

The specific arrangement of atoms that characterize a particular stereoisomer is known as (a) tautomer (b) conformation (c) configuration (d) geometry

Significant dipole moment is shown by (a) p-dichlorobenzene (b) \(\mathrm{CO}_{2}\) (c) cis 1,2-dichloroethene (d) trans 1,2 dichloro 1 -pentene

Zero inductive effect is shown by (a) \(-\mathrm{CH}_{3}\) (b) \(-\mathrm{H}\) (c) \(-\mathrm{D}\) (d) \(-\mathrm{C}_{6} \mathrm{H}_{5}\)
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