Chapter 1: Problem 125
The boiling point of \(\mathrm{CH} 3 \mathrm{OH}\) is \(65^{\circ} \mathrm{C}\), while the boiling point of \(\mathrm{CH} 3 \mathrm{SH}\) is only \(6^{\circ} \mathrm{C}\). Explain this difference in boiling point.
Short Answer
Expert verified
Explain why methanol (CH3OH) has a higher boiling point than methanethiol (CH3SH).
Methanol has a higher boiling point than methanethiol due to stronger intermolecular forces, specifically hydrogen bonding. In methanol, the oxygen atom forms hydrogen bonds due to its higher electronegativity, which requires more energy to be broken. In contrast, methanethiol has weaker dipole-dipole interactions and cannot form hydrogen bonds, resulting in a lower boiling point.
Step by step solution
01
Identify the molecules and the dominant intermolecular forces
Methanol (\(\mathrm{CH}3\mathrm{OH}\)) and methanethiol (\(\mathrm{CH}3\mathrm{SH}\)) are the two molecules in question. The primary intermolecular forces present in these molecules are hydrogen bonding, dipole-dipole interactions, and London dispersion forces. However, hydrogen bonding will have significant impacts on their boiling points.
02
Determine the presence of hydrogen bonding
Hydrogen bonding occurs when the hydrogen atom in a polar molecule is bonded to an electronegative atom and interacts with another electronegative atom in a neighboring molecule. In this context, oxygen and sulfur are the electronegative atoms. Methanol has an \(\mathrm{O-H}\) bond, which allows it to participate in hydrogen bonding; however, methanethiol has an \(\mathrm{S-H}\) bond, making it incapable of forming hydrogen bonds.
03
Compare electronegativities
Oxygen is more electronegative than sulfur, and as a result, it attracts bonded electrons more closely. This results in a more significant partial positive charge on the hydrogen atom in the \(\mathrm{O-H}\) bond. This charge difference increases the strength of hydrogen bonding in \(\mathrm{CH}3\mathrm{OH}\) compared to the weak dipole-dipole interactions in \(\mathrm{CH}3\mathrm{SH}\).
04
Relate intermolecular forces to boiling points
A higher boiling point is a result of stronger intermolecular forces, which require more energy to be overcome. Since \(\mathrm{CH}3\mathrm{OH}\) has stronger hydrogen bonding, which is a stronger intermolecular force than the dipole-dipole interactions in \(\mathrm{CH}3\mathrm{SH}\), more energy is needed to break these hydrogen bonds. Thus, methanol has a higher boiling point than methanethiol.
05
Summarize the findings
The difference in boiling points between \(\mathrm{CH}3\mathrm{OH}\) and \(\mathrm{CH}3\mathrm{SH}\) can be explained by the difference in their intermolecular forces. Methanol (\(\mathrm{CH}3\mathrm{OH}\)) forms stronger hydrogen bonds due to its oxygen atom compared to the weaker dipole-dipole interactions in methanethiol (\(\mathrm{CH}3\mathrm{SH}\)). This leads to a higher boiling point of \(65^{\circ}\mathrm{C}\) for \(\mathrm{CH}3\mathrm{OH}\) compared to \(6^{\circ}\mathrm{C}\) for \(\mathrm{CH}3\mathrm{SH}\).
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Key Concepts
These are the key concepts you need to understand to accurately answer the question.
Intermolecular Forces
Understanding intermolecular forces is essential when determining the physical properties of substances, such as boiling points. These forces are the attractions that occur between neighboring molecules. They vary in strength based on the types of particles involved and their proximity. In our exercise, we notice a significant difference in the boiling points of two organic compounds, methanol (CH3OH) and methanethiol (CH3SH), which can be attributed to the kinds of intermolecular forces present.
There are three main types of intermolecular forces: London dispersion forces, dipole-dipole interactions, and hydrogen bonding. London dispersion forces are the weakest and come into play between all molecules, whether polar or nonpolar, due to the momentary distribution of electrons. Dipole-dipole interactions occur when the positive end of a polar molecule is attracted to the negative end of another. These are stronger than London forces but still weaker than the third type, which greatly affects boiling points—hydrogen bonding.
There are three main types of intermolecular forces: London dispersion forces, dipole-dipole interactions, and hydrogen bonding. London dispersion forces are the weakest and come into play between all molecules, whether polar or nonpolar, due to the momentary distribution of electrons. Dipole-dipole interactions occur when the positive end of a polar molecule is attracted to the negative end of another. These are stronger than London forces but still weaker than the third type, which greatly affects boiling points—hydrogen bonding.
Role in Boiling Points
The energy required to boil a liquid is essentially the energy needed to overcome its intermolecular forces. Substances with stronger intermolecular forces have higher boiling points because it takes more energy to separate the molecules. This is why the study of these forces is critical when analyzing why molecules behave differently under heat.Hydrogen Bonding
Hydrogen bonding, a unique and strong type of dipole-dipole interaction, plays a pivotal role in explaining the higher boiling point of methanol compared to methanethiol. For hydrogen bonds to occur, a molecule must feature a hydrogen atom bonded to an electronegative element such as oxygen, nitrogen, or fluorine. This hydrogen develops a strong attraction to a lone pair of electrons on an electronegative atom in another molecule, creating a bridge-like bond.
Methanol exhibits hydrogen bonding because it has an O-H bond with oxygen's electronegativity pulling electron density away from hydrogen, making it partially positive. This enables it to strongly attract nearby electronegative atoms with lone pairs, just like magnets. Methanethiol, however, contains an S-H bond, and since sulfur is less electronegative than oxygen, the attraction is weaker, and hydrogen bonds do not form significantly.
Methanol exhibits hydrogen bonding because it has an O-H bond with oxygen's electronegativity pulling electron density away from hydrogen, making it partially positive. This enables it to strongly attract nearby electronegative atoms with lone pairs, just like magnets. Methanethiol, however, contains an S-H bond, and since sulfur is less electronegative than oxygen, the attraction is weaker, and hydrogen bonds do not form significantly.
Impact on Physical Properties
Hydrogen bonds are intrinsically strong due to the significant difference in electronegativity between hydrogen and atoms like oxygen. This strength needs more thermal energy to be broken, leading to high boiling points. Methanol's capacity to form these bonds results in a boiling point of 65°C. Methanethiol cannot establish these strong interactions and has a much lower boiling point of only 6°C.Electronegativity
Electronegativity is a concept that helps us understand why different atoms have different abilities to attract electrons when forming chemical bonds. Atoms closer to the top right of the periodic table – except for the noble gases – are generally more electronegative. Oxygen, for instance, is highly electronegative and strongly attracts electrons in covalent bonds.
The disparity in electronegativity between elements is a crucial factor when considering the strength of hydrogen bonds. For hydrogen bonding to be robust, as seen in methanol, the bonded electronegative atom must be able to attract electrons towards itself effectively, creating a significant partial positive charge on the hydrogen atom. In contrast, sulfur is less electronegative than oxygen, so the S-H bond in methanethiol generates a less pronounced charge separation, leading to weaker attractions between molecules and thus a lower boiling point.
The disparity in electronegativity between elements is a crucial factor when considering the strength of hydrogen bonds. For hydrogen bonding to be robust, as seen in methanol, the bonded electronegative atom must be able to attract electrons towards itself effectively, creating a significant partial positive charge on the hydrogen atom. In contrast, sulfur is less electronegative than oxygen, so the S-H bond in methanethiol generates a less pronounced charge separation, leading to weaker attractions between molecules and thus a lower boiling point.