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Chapter 1: Problem 132

The IUPAC name of \(\quad 1\) is CCC(C)CC(CC)CC (a) 5 -heptenylheptane (b) 3 -heptylhept-3-ene (c) 3 -(3-heptyl) hept-3-ene (d) 5,6-Diethyl-3-methyldec-4-ene

Short Answer

Expert verified
Answer: The correct IUPAC name for the compound is 3-ethyl-6-propylhept-3-ene.

Step by step solution

01

Count the carbon atoms of the longest chain

For the given compound, we need to find the longest continuous chain of carbon atoms. The SMILES notation is "CCC(C)CC(CC)CC", which translates to a structure with a chain of 5 carbon atoms with two branches.
02

Identify the functional groups and find their position

After identifying the longest carbon chain, we should now look for any functional groups present in the compound. In this case, there is an alkene functional group, which is a carbon-carbon double bond. The double bond is present between the 3rd and 4th carbon atoms, making the compound an alkene.
03

Locate and name the substituents

Now we need to find and name the substituents on the longest chain. There are two substituents: an ethyl group (C2H5) on the 3rd carbon atom and a propyl group (C3H7) on the 6th carbon atom.
04

Name the compound using IUPAC rules

Following IUPAC rules, we can name this compound by combining the information from steps 1-3. Firstly, name the longest chain with the appropriate alkene suffix (i.e., "hept-3-ene"). Secondly, include the substituent names along with their position in the chain, separated by hyphens. The compound can be named as 3-ethyl-6-propylhept-3-ene.
05

Compare the correct IUPAC name with the options provided

Now that we have determined the correct IUPAC name for the compound, we can compare it with the given options: (a) 5-heptenylheptane (b) 3-heptylhept-3-ene (c) 3-(3-heptyl)hept-3-ene (d) 5,6-Diethyl-3-methyldec-4-ene None of the provided options match the correct IUPAC name, indicating an error or inconsistency in this exercise.

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Most popular questions from this chapter

Configuration of a chiral molecule can be changed only if (a) the compound is rotated out of the plane of paper. (b) the confirmation is changed by rotation. (c) the Fischer projection is changed to the Newman projection. (d) the bond to the chiral carbon is broken.

Identify a statement which is not correct among the following (a) \(\mathrm{C}_{6} \mathrm{H}_{5}\) group in \(\mathrm{C}_{6} \mathrm{H}_{5} \mathrm{M}_{8} \mathrm{Cl}\) acts as an electrophile. (b) The two nonbonded electrons of a singlet carbene occupy the same orbital. (c) The stability of the alkyl carbocation is influenced by resonance. (d) Free radicals are formed in a homolytic bond fission.

The boiling point of \(\mathrm{CH} 3 \mathrm{OH}\) is \(65^{\circ} \mathrm{C}\), while the boiling point of \(\mathrm{CH} 3 \mathrm{SH}\) is only \(6^{\circ} \mathrm{C}\). Explain this difference in boiling point.

Statement 1 Alkyl carbanion such as \(\mathrm{CH}_{3}^{-}\) has pyramidal shape. and Statement 2 The carbon atom carrying the negative charge has an octet of electrons.

The correct decreasing order of acidity is (a) \(\mathrm{C}_{6} \mathrm{H}_{5} \mathrm{OH}>\mathrm{HC}=\mathrm{CH}>\mathrm{H}_{2} \mathrm{O}>\mathrm{NH}_{3}\) (b) \(\mathrm{C}_{6} \mathrm{H}_{5} \mathrm{OH}>\mathrm{C}_{2} \mathrm{H}_{5} \mathrm{OH}>\mathrm{NH}_{3}>\mathrm{HC}=\mathrm{CH}\) (c) \(\mathrm{HC}=\mathrm{CH}>\mathrm{C}_{6} \mathrm{H}_{5} \mathrm{OH}>\mathrm{H}_{2} \mathrm{O}>\mathrm{NH}_{3}\) (d) \(\mathrm{C}_{6} \mathrm{H}_{5} \mathrm{OH}>\mathrm{H}_{2} \mathrm{O}>\mathrm{C}_{2} \mathrm{H}_{5} \mathrm{OH}>\mathrm{HC}=\mathrm{CH}\)
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