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Chapter 1: Problem 136

The compound which has only one isopropyl group is (a) \(2,2,2,3\) -tetramethyl pentane (b) 2,4 -dimethyl pentane (c) \(2,2,3\) -tri methyl pentane (d) 2 -methyl pentane

Short Answer

Expert verified
Answer: 2,2,3 -trimethyl pentane

Step by step solution

01

Analyze option (a), \(2,2,2,3\) -tetramethyl pentane

The compound for option (a) has four methyl groups distributed on a pentane backbone, which is a five-carbon chain. As there are more than two methyl groups in this compound, there can't be an isopropyl group, because the isopropyl group must have only two methyl groups.
02

Analyze option (b), 2,4 -dimethyl pentane

The compound for option (b) has two methyl groups distributed on a pentane backbone. The two methyl groups are attached on the second and fourth carbon atoms, which doesn't form an isopropyl group. To form an isopropyl group, both the methyl groups need to be connected to the same central carbon atom.
03

Analyze option (c) \(2,2,3\) -tri methyl pentane

The compound for option (c) has three methyl groups distributed on a pentane backbone. Two of these methyl groups are on carbon 2, while the third methyl group is on carbon 3. Since there are two methyl groups attached to the same carbon atom (carbon 2), this forms an isopropyl group.
04

Analyze option (d) 2 -methyl pentane

The compound for option (d) has only one methyl group on a pentane backbone. This eliminates the possibility of the presence of an isopropyl group because you need at least two methyl groups attached to the same carbon atom for that to happen.
05

Identify the correct answer

Based on the analysis done in steps 1-4, the compound which has only one isopropyl group is the compound given in option (c), \(2,2,3\) -tri methyl pentane.

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Most popular questions from this chapter

The IUPAC name of (a) 3 -Methyl pent- 2 -en- 1 -ol (b) 2 -Ethyl pent- 2 -en-5-ol (c) 3 -Ethyl-but-2-en-1-ol (d) 3 , 3 -Methyl ethyl prop-2-en-1-ol

The correct decreasing order of nucleophilicity of the following ions for \(\mathrm{S}_{\mathrm{N}}{ }^{2}\) reactions in protic solvents is (a) \(\mathrm{PhS}^{-}>\mathrm{PhO}^{-}>\mathrm{OH}^{-}>\mathrm{C}_{2} \mathrm{H}_{5} \mathrm{O}^{-}>\mathrm{CN}^{-}\) (b) \(\mathrm{PhS}^{-}>\mathrm{CN}^{-}>\mathrm{C}_{2} \mathrm{H}_{5} \mathrm{O}^{-}>\mathrm{OH}^{-}>\mathrm{PhO}^{-}\) (c) \(\mathrm{CN}^{-}>\mathrm{OH}^{-}>\mathrm{C}, \mathrm{H}_{5} \mathrm{O}^{-}>\mathrm{PhS}^{-}>\mathrm{PhO}^{-}\) (d) \(\mathrm{C}, \mathrm{H}, \mathrm{O}^{-}>\mathrm{CN}^{-}>\mathrm{OH}^{-}>\mathrm{PhO}^{-}>\mathrm{PhS}^{-}\)

When (-) 3-Methyl pent-1-ene undergoes catalytic hydrogenation, (a) the product obtained has \((+)\) rotation (b) the product is obtained with retention of configuration (c) an optically inactive product is obtained (d) a racemic mixture is obtained

Which of the following statements is/are correct about H-bonding? (a) \(\mathrm{n}\) -Butanol has a higher boiling point than diethylether on account of intramolecular H-bonding. (b) Maleic acid is a stronger acid than fumaric acid due to the stabilization of the resulting anion by intramolecular H-bonding. (c) \(\mathrm{p}\) -nitrophenol is steam volatile due to intramolecular hydrogen bonding. (d) Hydrogen bond formation intramolecularly involving one molecule only is known as chelation and when formed intermolecularly is known as association.

In benzene all the \(\mathrm{C}-\mathrm{C}\) bonds are of equal length because of (a) resonance (b) aromaticity (c) hyperconjugation (d) tautomerism
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