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Chapter 1: Problem 165

The maximum number of isomers for the compound with molecular formula C IBrClF is (a) 4 (b) 5 (c) 6 (d) 7

Short Answer

Expert verified
Answer: The maximum number of isomers for a compound with the molecular formula C IBrClF is 5.

Step by step solution

01

Draw the carbon atom as the central atom

Since the molecular formula contains only one carbon atom, it must be at the center of the compound. Draw the carbon atom at the center of your structure.
02

Draw possible arrangements of atoms around carbon

Now, attach the four different halogens (I, Br, Cl, and F) to the carbon atom. Remember that carbon can form four bonds, so try to arrange the atoms in different configurations to form unique structures.
03

Identify unique isomers

Next, analyze the different structures you have drawn and identify which are unique isomers. Two structures are considered isomeric if they cannot be superimposed on one another and have a distinct three-dimensional configuration.
04

Count the number of unique isomers

After identifying the unique isomers, count them to determine the maximum number of isomers for the compound with the molecular formula C IBrClF. Here are the possible isomers of C IBrClF: 1. C(I)(Br)(Cl)(F) 2. C(I)(F)(Br)(Cl) 3. C(I)(Cl)(F)(Br) 4. C(I)(Br)(F)(Cl) 5. C(I)(F)(Cl)(Br) Upon analyzing these structures, we can see that there are 5 unique isomers for the compound. So, the correct answer is (b) 5.

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Most popular questions from this chapter

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