Log out Go to App
Go to App

Learning Materials

Features

Discover

Chapter 1: Problem 182

A chemical reaction is one in which old bonds are broken and new bonds are made. During the course of these changes a variety of intermediates are formed before a starting material is converted to final products. Formation of these intermediates depend on several factors like bond energies, kinetics of the reactions etc. Identify the correct statement among the following. (a) An electrophile has always a positive charge. (b) \(\mathrm{CN}^{-}\) can act as an ambident nucleophile. (c) The carbon species A formed is a methyl carbanion. (d) In \(\mathrm{CH}_{3} \mathrm{MgBr}\), the methyl group carries slight positive charge.

Short Answer

Expert verified
(a) An electrophile always has a positive charge. (b) \(\mathrm{CN}^{-}\) can act as an ambident nucleophile. (c) The carbon species A formed is a methyl carbanion. (d) In \(\mathrm{CH}_{3} \mathrm{MgBr}\), the methyl group carries a slight positive charge. Answer: (b) \(\mathrm{CN}^{-}\) can act as an ambident nucleophile.

Step by step solution

01

Analyzing Statement A

Statement A says that an electrophile always has a positive charge. This statement is not entirely correct, as an electrophile is a species that accepts electron pairs and can have a positive charge, no charge, or even a partial positive charge.
02

Analyzing Statement B

Statement B says that \(\mathrm{CN}^{-}\) can act as an ambident nucleophile. This statement is true. An ambident nucleophile is a nucleophile that can attack from two different atoms. In the case of \(\mathrm{CN}^{-}\), the cyanide ion can attack either through the carbon or nitrogen atom, making it an ambident nucleophile.
03

Analyzing Statement C

Statement C says that the carbon species A formed is a methyl carbanion. We don't have enough information about species A to determine if it is a methyl carbanion. Thus, we can't identify the correctness of this statement.
04

Analyzing Statement D

Statement D says that in \(\mathrm{CH}_{3} \mathrm{MgBr}\), the methyl group carries a slight positive charge. This statement is incorrect. In \(\mathrm{CH}_{3} \mathrm{MgBr}\) (also known as Grignard reagent), magnesium has a positive charge while the methyl group (directly bonded with Mg) has a partial negative charge, which makes the carbon of methyl group more nucleophilic. Therefore, the correct statement among the given options is: (b) \(\mathrm{CN}^{-}\) can act as an ambident nucleophile.

Unlock Step-by-Step Solutions & Ace Your Exams!

  • Full Textbook Solutions

    Get detailed explanations and key concepts

  • Unlimited Al creation

    Al flashcards, explanations, exams and more...

  • Ads-free access

    To over 500 millions flashcards

  • Money-back guarantee

    We refund you if you fail your exam.

Start your free trial

Over 30 million students worldwide already upgrade their learning with Vaia!

One App. One Place for Learning.

All the tools & learning materials you need for study success - in one app.

Get started for free

Most popular questions from this chapter

The specific rotation of a pure optically active compound is \(+12^{\circ} .\) The specific rotation of the sample in a reaction with \(20 \%\) racemization and \(80 \%\) retension of configuration will be (a) \(+12^{\circ}\) (b) \(-12^{\circ}\) (c) \(+9.6^{\circ}\) (d) \(-2.4^{\circ}\)

IUPAC name of the compound (a) Trans-3,4-dimethylhex-3-ene (b) Cis- 3,4 -dimethylhex-3-ene (c) Cis- 3,4 -dimethylhex-4-ene (d) Cis-2,3-diethylbut-2-ene

The most stable free radical among the following is (a) C=CC(C)C (b) c1ccccc1 (c) \(\left(\mathrm{CH}_{3}\right)_{3} \mathrm{C}\) (d) \(\mathrm{CH}_{2}=\mathrm{CH}-\mathrm{CH}_{2}-\mathrm{CH}_{2}\).

The isomeric cis \(-2\) -butene and trans 2 -butene differ in (a) the products obtained by addition of \(\mathrm{HBr}\) (b) their reduction products on hydrogenation (c) their products on ozonolysis (d) the products they give on bromine addition

A set which contains an electrophile, a Lewis base and a species containing unpaired electrons among the following is (a) \(\mathrm{Cl}^{-}, \mathrm{AlCl}_{3}\) and \(\mathrm{H}_{2}\) (b) \(\mathrm{SO}_{3},\left(\mathrm{CH}_{3}\right)_{2} \mathrm{O}\), triplet carbene (c) \(\mathrm{Cl}^{-}, \mathrm{HCl}\) and singlet carbene
See all solutions

Recommended explanations on Chemistry Textbooks

Inorganic Chemistry

Read Explanation

Physical Chemistry

Read Explanation

Nuclear Chemistry

Read Explanation

Making Measurements

Read Explanation

The Earths Atmosphere

Read Explanation

Chemical Reactions

Read Explanation
View all explanations

What do you think about this solution?

We value your feedback to improve our textbook solutions.

Study anywhere. Anytime. Across all devices.

Sign-up for free