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Chapter 1: Problem 30

Match the elements of Column I to elements of Column II. There can be single or multiple matches. Column I (a) \(\mathrm{CH}_{3}-\mathrm{CH}_{2}-\mathrm{CH}_{2}{ }^{+}\) (b) Buta- 1,3 -diene (c) \(\mathrm{CH}_{3}-\dot{\mathrm{C}} \mathrm{H}_{2}\) (d) Benzene. Column II (p) Conjugation (q) Hyperconjugation (r) \(\mathrm{sp}^{2}\) hybridized carbon (s) Rearrangement

Short Answer

Expert verified
a. Conjugation b. Delocalization of electrons c. Hyperconjugation d. Carbocation rearrangement e. \(\mathrm{sp}^{2}\) hybridization Answer: c, d, e

Step by step solution

01

Understanding and Analyzing Element (a) - \(\mathrm{CH}_{3}-\mathrm{CH}_{2}-\mathrm{CH}_{2}{ }^{+}\)

This species is a carbocation with a positively charged carbon atom. The positively charged carbon is \(\mathrm{sp}^{2}\) hybridized, and there is hyperconjugation, which involves the overlap of adjacent C-H bonds with the empty p-orbital on the positive carbon atom. Rearrangement is possible in this species where a neighboring hydrogen or alkyl group could shift to stabilize the carbocation.
02

Understanding and Analyzing Element (b) - Buta-1,3-diene

Buta-1,3-diene is a molecule with alternate single and double bonds. Due to the presence of conjugated double bonds, we can consider the conjugation effect. Here, the double bonds involve the \(\mathrm{sp}^{2}\) hybridized carbons.
03

Understanding and Analyzing Element (c) - \(\mathrm{CH}_{3}-\dot{\mathrm{C}} \mathrm{H}_{2}\)

This species is a carbon-radical, where the central carbon has an unpaired electron in one of its p-orbitals. The carbon radical is \(\mathrm{sp}^{2}\) hybridized.
04

Understanding and Analyzing Element (d) - Benzene

Benzene is a cyclic, aromatic compound with conjugated double bonds (alternating single and double bonds). All six carbon atoms in the ring are \(\mathrm{sp}^{2}\) hybridized. It's important to note that there is a delocalized cloud of electrons above and below the ring due to pi bond conjugation.
05

Matching Column I elements to Column II elements

(a) \(\Rightarrow\) (q), (r), (s) (b) \(\Rightarrow\) (p), (r) (c) \(\Rightarrow\) (r) (d) \(\Rightarrow\) (p), (r) By analyzing the four elements of Column I and identifying their properties, we have successfully matched them to the appropriate elements in Column II.

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Most popular questions from this chapter

The correct decreasing order of acidity is (a) \(\mathrm{C}_{6} \mathrm{H}_{5} \mathrm{OH}>\mathrm{HC}=\mathrm{CH}>\mathrm{H}_{2} \mathrm{O}>\mathrm{NH}_{3}\) (b) \(\mathrm{C}_{6} \mathrm{H}_{5} \mathrm{OH}>\mathrm{C}_{2} \mathrm{H}_{5} \mathrm{OH}>\mathrm{NH}_{3}>\mathrm{HC}=\mathrm{CH}\) (c) \(\mathrm{HC}=\mathrm{CH}>\mathrm{C}_{6} \mathrm{H}_{5} \mathrm{OH}>\mathrm{H}_{2} \mathrm{O}>\mathrm{NH}_{3}\) (d) \(\mathrm{C}_{6} \mathrm{H}_{5} \mathrm{OH}>\mathrm{H}_{2} \mathrm{O}>\mathrm{C}_{2} \mathrm{H}_{5} \mathrm{OH}>\mathrm{HC}=\mathrm{CH}\)

The maximum number of isomers for the compound with molecular formula C IBrClF is (a) 4 (b) 5 (c) 6 (d) 7

A chemical reaction is one in which old bonds are broken and new bonds are made. During the course of these changes a variety of intermediates are formed before a starting material is converted to final products. Formation of these intermediates depend on several factors like bond energies, kinetics of the reactions etc. In which of the following choices, the correct order is not indicated. (a) \(\mathrm{F}^{-}<\mathrm{Cl}^{-}<\mathrm{Br}^{-}<\mathrm{I}^{-}(\) the order of base strength \()\) (b) \(\mathrm{ClCH}_{2} \underset{\oplus}{\mathrm{C}}\left(\mathrm{CH}_{3}\right)_{2}<\left(\mathrm{CH}_{3}\right)_{3} \mathrm{C}<\left(\mathrm{CH}_{3}\right)_{2} \mathrm{COCH}_{3}\) (stability of carbocation) (c) \(\mathrm{O}_{2} \mathrm{~N}-\mathrm{CH}_{2}>\mathrm{CH}_{3}>\mathrm{CH}_{3} \mathrm{CH}_{2}\) (stability of carbanion) (d) \(\mathrm{H}_{2} \mathrm{C}=\mathrm{CH}_{2}<\mathrm{CH}_{3} \mathrm{CH}=\mathrm{CHCH}_{3}<\left(\mathrm{CH}_{3}\right)_{2} \mathrm{C}=\mathrm{C}\left(\mathrm{CH}_{3}\right)_{2}\) (stability of alkenes)

Arrange the acids (I-V) listed below in the decreasing order of their acid strength and justify. (i) Butanoic acid (ii) Trichloro acetic acid (iii) Chloroacetic acid (iv) Trimethyl acetic acid (v) Bromo acetic acid

An allylic carbocation is less stable than (a) a vinyl cation (b) neopentyl cation (c) benzylic cation (d) \(\mathrm{CH}_{3}-\mathrm{CH}=\mathrm{CH}-\mathrm{CH}_{2}-\mathrm{CH}_{2}^{+}\)
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