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Chapter 1: Problem 30

Match the elements of Column I to elements of Column II. There can be single or multiple matches. Column I (a) \(\mathrm{CH}_{3}-\mathrm{CH}_{2}-\mathrm{CH}_{2}{ }^{+}\) (b) Buta- 1,3 -diene (c) \(\mathrm{CH}_{3}-\dot{\mathrm{C}} \mathrm{H}_{2}\) (d) Benzene. Column II (p) Conjugation (q) Hyperconjugation (r) \(\mathrm{sp}^{2}\) hybridized carbon (s) Rearrangement

Short Answer

Expert verified
a. Conjugation b. Delocalization of electrons c. Hyperconjugation d. Carbocation rearrangement e. \(\mathrm{sp}^{2}\) hybridization Answer: c, d, e

Step by step solution

01

Understanding and Analyzing Element (a) - \(\mathrm{CH}_{3}-\mathrm{CH}_{2}-\mathrm{CH}_{2}{ }^{+}\)

This species is a carbocation with a positively charged carbon atom. The positively charged carbon is \(\mathrm{sp}^{2}\) hybridized, and there is hyperconjugation, which involves the overlap of adjacent C-H bonds with the empty p-orbital on the positive carbon atom. Rearrangement is possible in this species where a neighboring hydrogen or alkyl group could shift to stabilize the carbocation.
02

Understanding and Analyzing Element (b) - Buta-1,3-diene

Buta-1,3-diene is a molecule with alternate single and double bonds. Due to the presence of conjugated double bonds, we can consider the conjugation effect. Here, the double bonds involve the \(\mathrm{sp}^{2}\) hybridized carbons.
03

Understanding and Analyzing Element (c) - \(\mathrm{CH}_{3}-\dot{\mathrm{C}} \mathrm{H}_{2}\)

This species is a carbon-radical, where the central carbon has an unpaired electron in one of its p-orbitals. The carbon radical is \(\mathrm{sp}^{2}\) hybridized.
04

Understanding and Analyzing Element (d) - Benzene

Benzene is a cyclic, aromatic compound with conjugated double bonds (alternating single and double bonds). All six carbon atoms in the ring are \(\mathrm{sp}^{2}\) hybridized. It's important to note that there is a delocalized cloud of electrons above and below the ring due to pi bond conjugation.
05

Matching Column I elements to Column II elements

(a) \(\Rightarrow\) (q), (r), (s) (b) \(\Rightarrow\) (p), (r) (c) \(\Rightarrow\) (r) (d) \(\Rightarrow\) (p), (r) By analyzing the four elements of Column I and identifying their properties, we have successfully matched them to the appropriate elements in Column II.

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Most popular questions from this chapter

When (-) lactic acid is treated with methanol under acidic conditions, (+) methyl lactate, an ester, is obtained as the product. Has the configuration at chiral centre changed?

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The maximum number of isomers for the compound with molecular formula C IBrClF is (a) 4 (b) 5 (c) 6 (d) 7

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