Log out Go to App
Go to App

Learning Materials

Features

Discover

Chapter 1: Problem 52

A meso compound (a) is an achiral molecule, which contain chiral carbons. (b) contains a plane of symmetry or a centre of symmetry. (c) is optically inactive due to internal compensation. (d) is characterized by all the above.

Short Answer

Expert verified
a) an achiral molecule which contains chiral carbons b) contains a plane of symmetry or a center of symmetry c) is optically inactive due to internal compensation Answer: Statements (b) and (c) accurately describe a meso compound.

Step by step solution

01

Analyze statement (a)

Statement (a) says that a meso compound is an achiral molecule which contains chiral carbons. This statement is partially correct, as meso compounds do have chiral centers. However, meso compounds are not considered achiral, as they have an internal plane of symmetry, causing them to be optically inactive.
02

Analyze statement (b)

Statement (b) says that a meso compound contains a plane of symmetry or a center of symmetry. This statement is correct as meso compounds have an internal plane of symmetry. This characteristic is a defining feature of meso compounds.
03

Analyze statement (c)

Statement (c) says that a meso compound is optically inactive due to internal compensation. This statement is accurate, as the internal plane of symmetry causes the compound to be optically inactive, despite having chiral centers.
04

Analyze statement (d)

Statement (d) says that a meso compound is characterized by all the above statements. As we analyzed each statement and found that (b) and (c) are correct, while statement (a) is partially correct, statement (d) is not entirely accurate.
05

Determine the correct answer

Based on our analysis, statement (b) and statement (c) accurately describe a meso compound. Statement (a) is only partially correct, and statement (d) is not entirely accurate since statement (a) is not completely correct. Therefore, the answer is a combination of statement (b) and statement (c), as both of these correctly describe a meso compound.

Unlock Step-by-Step Solutions & Ace Your Exams!

  • Full Textbook Solutions

    Get detailed explanations and key concepts

  • Unlimited Al creation

    Al flashcards, explanations, exams and more...

  • Ads-free access

    To over 500 millions flashcards

  • Money-back guarantee

    We refund you if you fail your exam.

Start your free trial

Over 30 million students worldwide already upgrade their learning with Vaia!

One App. One Place for Learning.

All the tools & learning materials you need for study success - in one app.

Get started for free

Most popular questions from this chapter

A free radical is (a) generated by a heterolytic cleavage (b) paramagnetic (c) generally more stable than a carbanion (d) produced in an ionic reaction

A chemical reaction is one in which old bonds are broken and new bonds are made. During the course of these changes a variety of intermediates are formed before a starting material is converted to final products. Formation of these intermediates depend on several factors like bond energies, kinetics of the reactions etc. Identify the correct statement among the following. (a) An electrophile has always a positive charge. (b) \(\mathrm{CN}^{-}\) can act as an ambident nucleophile. (c) The carbon species A formed is a methyl carbanion. (d) In \(\mathrm{CH}_{3} \mathrm{MgBr}\), the methyl group carries slight positive charge.

Identify the correct statements among the following. (a) Acetate ion ( \(\left.\mathrm{CH}_{3}-\mathrm{COO}^{-}\right)\) is a weaker base than ethoxide ion \(\left(\mathrm{C}_{2} \mathrm{H}_{5} \mathrm{O}^{-}\right)\). (b) HF has higher boiling point than HCl. (c) Tartaric acid (HOOC - CHOH - CHOH - COOH) has three optically active isomers. (d) \(\mathrm{C}_{3} \mathrm{H}_{7} \mathrm{CN}\) is known as propyl cyanide as well as butane nitrile.

Choose the correct compound/species from P-S according to the property indicated in each. (P) The stronger acid of the two \(\left(\mathrm{CH}_{3}\right)_{2} \underset{(\mathrm{I})}{\mathrm{NH}}\) or \(\left(\mathrm{CH}_{3}\right)_{2} \mathrm{O} \mathrm{H}\) (Q) The stronger base of the two \(\left(\mathrm{CH}_{3}\right)_{3} \ddot{\mathrm{N}}\) or \(\left(\mathrm{CH}_{3}\right)_{2} \mathrm{O}\) (III) (R) The stronger acid of the two \(\mathrm{H}_{2} \mathrm{O}\) or \(\mathrm{H}_{2} \mathrm{~S}\) "1 (S) The stronger base of the two \(\mathrm{OH}\) or \(\mathrm{SH}\) (a) \(\mathrm{P}-\mathrm{II}, \mathrm{Q}-\mathrm{III}, \mathrm{R}-\mathrm{VI}, \mathrm{S}-\mathrm{VII}\) (b) \(\mathrm{P}-\mathrm{I}, \mathrm{Q}-\mathrm{III}, \mathrm{R}-\mathrm{V}, \mathrm{S}-\mathrm{VIII}\) (c) \(\mathrm{P}-\mathrm{II}, \mathrm{Q}-\mathrm{IV}, \mathrm{R}-\mathrm{V}, \mathrm{S}-\mathrm{VIII}\) (d) \(\mathrm{P}-\mathrm{II}, \mathrm{Q}-\mathrm{III}, \mathrm{R}-\mathrm{V}, \mathrm{S}-\mathrm{VII}\)

The number of optically active stereoisomers possible for the compound 2,3 -dihydroxy butane are (a) 4 (b) 2 (c) 6 (d) 8
See all solutions

Recommended explanations on Chemistry Textbooks

Inorganic Chemistry

Read Explanation

Making Measurements

Read Explanation

Chemistry Branches

Read Explanation

Kinetics

Read Explanation

Physical Chemistry

Read Explanation

Ionic and Molecular Compounds

Read Explanation
View all explanations

What do you think about this solution?

We value your feedback to improve our textbook solutions.

Study anywhere. Anytime. Across all devices.

Sign-up for free