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Chapter 1: Problem 90

A compound can exhibit optical activity even if (a) a rotation axis is present (b) a mirror plane is present (c) a centre of symmetry is present (d) an alternating axis of symmetry is present

Short Answer

Expert verified
Answer: A compound can exhibit optical activity when a rotation axis is present.

Step by step solution

01

Option A: Rotation Axis

A molecule can have a rotation axis while still being chiral, which means it can exhibit optical activity. For example, chiral allenes have a C2 rotation axis, but they are still optically active because they lack a mirror plane, center of symmetry, and an alternating axis of symmetry. So, the answer (a) is correct.
02

Option B: Mirror Plane

If a molecule has a mirror plane, it means it has a plane of symmetry. By definition, a molecule with a plane of symmetry cannot exhibit optical activity, as it is achiral. Thus, this option is incorrect.
03

Option C: Centre of Symmetry

If a molecule has a center of symmetry, it is achiral. A center of symmetry is a point in the molecule such that any line that passes through the point and an atom or group of atoms leaves the molecule on a corresponding atom or group equidistant from the center. A molecule with a center of symmetry will not exhibit optical activity, making this option incorrect.
04

Option D: Alternating Axis of Symmetry

An alternating axis of symmetry is a rotation axis followed by a reflection in a plane perpendicular to the axis. When a molecule has an alternating axis of symmetry, it lacks chirality and cannot exhibit optical activity. Therefore, this option is incorrect. In conclusion, the correct answer is (a) a rotation axis is present.

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Most popular questions from this chapter

The correct decreasing order of acidity is (a) \(\mathrm{C}_{6} \mathrm{H}_{5} \mathrm{OH}>\mathrm{HC}=\mathrm{CH}>\mathrm{H}_{2} \mathrm{O}>\mathrm{NH}_{3}\) (b) \(\mathrm{C}_{6} \mathrm{H}_{5} \mathrm{OH}>\mathrm{C}_{2} \mathrm{H}_{5} \mathrm{OH}>\mathrm{NH}_{3}>\mathrm{HC}=\mathrm{CH}\) (c) \(\mathrm{HC}=\mathrm{CH}>\mathrm{C}_{6} \mathrm{H}_{5} \mathrm{OH}>\mathrm{H}_{2} \mathrm{O}>\mathrm{NH}_{3}\) (d) \(\mathrm{C}_{6} \mathrm{H}_{5} \mathrm{OH}>\mathrm{H}_{2} \mathrm{O}>\mathrm{C}_{2} \mathrm{H}_{5} \mathrm{OH}>\mathrm{HC}=\mathrm{CH}\)

When (-) lactic acid is treated with methanol under acidic conditions, (+) methyl lactate, an ester, is obtained as the product. Has the configuration at chiral centre changed?

Number of structural isomers possible for \(\mathrm{C}_{6} \mathrm{H}_{14}\) and \(\mathrm{C}_{7} \mathrm{H}_{16}\) are respectively (a) 5 and 7 (b) 5 and 9 (c) 6 and 7 (d) 4 and 8

Which of the following statements is/are correct about H-bonding? (a) \(\mathrm{n}\) -Butanol has a higher boiling point than diethylether on account of intramolecular H-bonding. (b) Maleic acid is a stronger acid than fumaric acid due to the stabilization of the resulting anion by intramolecular H-bonding. (c) \(\mathrm{p}\) -nitrophenol is steam volatile due to intramolecular hydrogen bonding. (d) Hydrogen bond formation intramolecularly involving one molecule only is known as chelation and when formed intermolecularly is known as association.

In which of the following reactions, new chiral centre(s) is/are generated. (a) \(\mathrm{CH}_{3}-\mathrm{CH}=\mathrm{CH}-\mathrm{CH}_{3} \stackrel{\text { Baeyer'sreagent }}{\longrightarrow}\) (b) \(\mathrm{CH}_{3} \mathrm{CH}=\mathrm{CH}-\mathrm{CH}_{3}+\mathrm{HBr} \rightarrow\) (c) (d) \(\mathrm{CH}_{3}-\mathrm{CH}=\mathrm{CH}_{2}+\mathrm{HCl} \rightarrow\)
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