Chapter 1: Problem 90
A compound can exhibit optical activity even if (a) a rotation axis is present (b) a mirror plane is present (c) a centre of symmetry is present (d) an alternating axis of symmetry is present
Chapter 1: Problem 90
A compound can exhibit optical activity even if (a) a rotation axis is present (b) a mirror plane is present (c) a centre of symmetry is present (d) an alternating axis of symmetry is present
All the tools & learning materials you need for study success - in one app.
Get started for freeA chemical reaction is one in which old bonds are broken and new bonds are made. During the course of these changes a variety of intermediates are formed before a starting material is converted to final products. Formation of these intermediates depend on several factors like bond energies, kinetics of the reactions etc. Identify the correct statement among the following. (a) An electrophile has always a positive charge. (b) \(\mathrm{CN}^{-}\) can act as an ambident nucleophile. (c) The carbon species A formed is a methyl carbanion. (d) In \(\mathrm{CH}_{3} \mathrm{MgBr}\), the methyl group carries slight positive charge.
Between \(\mathrm{CH}_{3} \mathrm{O} \mathrm{CH}_{2} \mathrm{CH}_{2}(\mathrm{I})\) and \(\mathrm{CH}_{3} \mathrm{CH}_{2} \mathrm{O} \mathrm{CH}_{2}(\mathrm{II})\) (a) I is more stable because it is \(1^{\circ}\) carbocation. (b) II is more stable because it is \(1^{\circ}\) carbocation. (c) II is more stable because the cation is stabilized by the lone pair on oxygen. (d) Both are equally stable since both the cations are \(1^{\circ}\) and stabilized by oxygen.
Two pairs of compounds are given below, which one in each is more acidic and
why?
(i) \(\mathrm{BrCH}_{2} \mathrm{CH}_{2} \mathrm{CH}_{2} \mathrm{OH}\) and
\(\mathrm{H}_{3} \mathrm{COCH}_{2} \mathrm{CH}_{2} \mathrm{CH}_{2}
\mathrm{CH}_{2} \mathrm{OH}\)
(ii) \(\mathrm{BrCH}_{2} \mathrm{CH}_{2} \mathrm{CH}_{2} \mathrm{OH}\) and
The IUPAC name of \(\mathrm{CH}_{3}-\mathrm{CO}-\mathrm{CHCl}-\mathrm{CH}_{2}-\mathrm{COOH}\) is (a) 3-Chloro-4-oxopentanoic acid (b) 4-Oxo-3-Chloropentanoic acid (c) 2-Oxo-3-Chloropentanoic acid (d) 1 -Carboxy-3-Chloro-4-ketobutane
The correct IUPAC name of \(\mathrm{CH}_{3}-\mathrm{O}-\mathrm{CH}_{2}-\mathrm{O}-\mathrm{CH}_{2}-\mathrm{O}-\mathrm{CH}_{3}\) is (a) \(1,3,5\) -Trioxabutane (b) \(2,4,6\) -Trioxabutane (c) \(2,4,6\) -Trioxaheptane (d) Dimethoxydimethyl ether
What do you think about this solution?
We value your feedback to improve our textbook solutions.