Chapter 2: Problem 11
The best method of preparation of an alkane with odd number of carbons from two alkylhalides is (a) Wurtz reaction (b) Kolbe's electrolysis (c) Corey-House synthesis (d) Ullmann reaction
Chapter 2: Problem 11
The best method of preparation of an alkane with odd number of carbons from two alkylhalides is (a) Wurtz reaction (b) Kolbe's electrolysis (c) Corey-House synthesis (d) Ullmann reaction
All the tools & learning materials you need for study success - in one app.
Get started for freeThe reactions of alkenes are mainly (a) nucleophilic additions (b) nucleophilic substitutions (c) free radical reactions (d) electrophilic additions
Identify the incorrect statement among the following (b) The dipole moment of \(\mathrm{CH}_{2} \mathrm{Cl}_{2}\) is greater than that of \(\mathrm{CH}_{3} \mathrm{Cl}\). (c) The cis isomers become increasingly less stable as the size of the \(\mathrm{R}\) groups increase. (d) Alkenes with two identical groups on the same doubly bonded carbon have no geometrical isomers.
1,6 Dibromohexane can be converted to cyclohexane, when treated with \(\mathrm{Na}\) or \(\mathrm{Zn}\), in the presence of a catalyst. This reaction is known as (a) Wurtz coupling (b) Dieckmann cyclization (c) Freund's method (d) Diels Alder reaction
\(\mathrm{HC} \equiv \mathrm{N}\) is more acidic than \(\mathrm{HC} \equiv \mathrm{CH}\) because (a) HCN is an acid whereas, \(\mathrm{HC} \equiv \mathrm{CH}\) is a hydrocarbon. (b) HCN has a pK of \(9.2\). (c) In addition to greater s character of the hybrid orbitals, the presence of more electronegative nitrogen further stabilizes the anion - CN. (d) of the triple bond nature of the \({ }^{-} \mathrm{C} \equiv \mathrm{N}\) bond.
HI does not exhibit peroxide effect because (a) HI is a reducing agent. (b) the iodine free radicals formed recombine readily to form the iodine molecule. (c) the bond energy of HI is very high that it does not undergo homolytic fission to give iodine radicals. (d) Free radical reactions work well when both the propagation steps are endothermic.
What do you think about this solution?
We value your feedback to improve our textbook solutions.