Chapter 2: Problem 110
The reagent that does not react with ethyne is (a) Ammoniacal \(\mathrm{AgNO}_{3}\) (b) \(\mathrm{NaOH}\) (c) \(\mathrm{HCl}\) (d) Na
Chapter 2: Problem 110
The reagent that does not react with ethyne is (a) Ammoniacal \(\mathrm{AgNO}_{3}\) (b) \(\mathrm{NaOH}\) (c) \(\mathrm{HCl}\) (d) Na
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Get started for freeThe cis hydroxylation of alkenes can be effected by (a) reaction with \(\mathrm{OsO}_{4}\) (b) addition of Baeyer's reagent (c) reaction with \(\mathrm{H}_{2} \mathrm{O}_{2}\) and formic acid (d) reaction with an acid in the presence of water.
Alkynes are less reactive than alkenes towards electrophilic reagents. But the alkyne chemistry is useful for organic synthesis, in the form of hydration of the triple bond, formation of metalacetylides, selective reduction of alkynes and few other related reactions.
\(\mathrm{CH}_{3} \mathrm{CH}_{2} \mathrm{CH}_{3} \stackrel{\mathrm{Br}_{2} / \mathrm{hv}}{\longrightarrow}(\mathrm{A}) \stackrel{\mathrm{Mg} / \mathrm{Ether}}{\longrightarrow}(\mathrm{B}) \stackrel{\mathrm{D}_{2} \mathrm{O}}{\longrightarrow}(\mathrm{C})\) The major product \(C\) formed is (a) \(\mathrm{CH}_{3} \mathrm{CH}_{2} \mathrm{CH}_{2} \mathrm{D}\) (b) \(\mathrm{CH}_{3} \mathrm{CH}_{2} \mathrm{CH}_{3}\) (c) \(\mathrm{CH}_{3} \mathrm{CHD} \mathrm{CH}_{3}\) (d)
When 3-methyl-2-butanol reacts with HBr, the expected product is 2-bromo-3-methyl-butane. But the actual product formed is 2 -bromo-2-methylbutane. Account for this.
This section contains multiple choice questions. Each question has 4 choices (a), (b), (c) and (d), out of which ONLY ONE is correct. A compound with the molecular formula, \(\mathrm{C}_{4} \mathrm{H}_{6}\), does not exist in cis or trans form. It does not produce a precipitate with ammoniacal \(\mathrm{AgNO}_{3}\) solution. The compound as such is optically inactive but a monohalogen derivative can be optically active. The compound is (a) \(\mathrm{CH}_{3} \mathrm{C} \equiv \mathrm{C}-\mathrm{CH}_{3}\) (b) \(\mathrm{CH}_{3}-\mathrm{CH}=\mathrm{C}=\mathrm{CH}_{2}\) (c) \(\mathrm{CH}_{3}-\mathrm{CH}_{2}-\mathrm{C} \equiv \mathrm{C}-\mathrm{H}\) (d)
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