Match the elements of Column I to elements of Column II. There can be single or multiple matches. Column I (a) Markovnikov addition (b) anti Markovnikov hydration (c) \(\mathrm{OsO}_{4}\) and an alkene (d) Catalytic hydrogenation Column II (p) 1-Butyne and HOCl (q) syn addition (r) Hydroboration-oxidation (s) Addition of HI to but-1-ene in the presence of \(\left(\mathrm{C}_{6} \mathrm{H}_{5} \mathrm{COO}\right)_{2}\)

Short Answer

Expert verified
Based on the given step-by-step solution: 1. Match the corresponding term of Markovnikov addition from Column II. Answer: (s) addition of HI to but-1-ene in the presence of \(\left(\mathrm{C}_{6}\mathrm{H}_{5}\mathrm{COO}\right)_{2}\)

Step by step solution

01

Understand the terms in Column I

In this step, learn the meaning of the terms given in Column I: (a) Markovnikov addition: A type of regioselective reaction where the addition of a protic reagent to an alkene results in the most stable carbocation intermediate. (b) Anti Markovnikov hydration: A type of regioselective reaction that adds a protic reagent to an alkene in a way that the most stable carbocation intermediate is not formed. (c) \(\mathrm{OsO}_{4}\) and an alkene: OsO4 is osmium tetroxide, which is a catalyst used in the dihydroxylation reaction. When reacting with an alkene, the syn addition of two hydroxyl groups results in a diol. (d) Catalytic hydrogenation: A chemical reaction in which hydrogen is added to a molecule in the presence of a catalyst (usually metal-based) to reduce a double or triple bond in an alkene or alkyne.
02

Recognize the corresponding terms in Column II

Now that we understand the terms from Column I, let's find the matching elements in Column II: (p) 1-Butyne and HOCl: The reaction of 1-butyne with HOCl results in the formation of an anti Markovnikov product with halogen and(OH) groups, making it related to (b) anti Markovnikov hydration. (q) syn addition: In a syn addition, two substituent groups are added to the same side of a double bond. This reaction corresponds to (c) \(\mathrm{OsO}_{4}\) and an alkene. (r) hydroboration-oxidation: This is a two-step reaction, and it converts alkenes into alcohols. The process occurs by anti Markovnikov hydration, and the final product is an alcohol. Therefore, it corresponds to (b) anti Markovnikov hydration. (s) addition of HI to but-1-ene in the presence of \(\left(\mathrm{C}_{6}\mathrm{H}_{5}\mathrm{COO}\right)_{2}\): In the presence of the \(\left(\mathrm{C}_{6}\mathrm{H}_{5}\mathrm{COO}\right)_{2}\), the reaction proceeds by Markovnikov addition. Thus, it corresponds to (a) Markovnikov addition.
03

Matching Column I with Column II

After understanding each term and finding the corresponding elements, match the elements of Column I with the elements of Column II: (a) Markovnikov addition -> (s) (b) anti Markovnikov hydration -> (p) & (r) (c) \(\mathrm{OsO}_{4}\) and an alkene -> (q) (d) Catalytic hydrogenation -> (not directly mentioned in Column II) The matching has been done successfully.

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Most popular questions from this chapter

The IUPAC name of the compound is (a) 6-bromo-2-chlorocyclohexene (b) 3-bromo-1-chlorocyclohexene (c) 1 -bromo-3-chlorocyclohexene (d) 2-bromo-6-chlorocyclohexene

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