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Chapter 2: Problem 133

This section contains multiple choice questions. Each question has 4 choices (a), (b), (c) and (d), out of which ONLY ONE is correct. A compound with the molecular formula, \(\mathrm{C}_{4} \mathrm{H}_{6}\), does not exist in cis or trans form. It does not produce a precipitate with ammoniacal \(\mathrm{AgNO}_{3}\) solution. The compound as such is optically inactive but a monohalogen derivative can be optically active. The compound is (a) \(\mathrm{CH}_{3} \mathrm{C} \equiv \mathrm{C}-\mathrm{CH}_{3}\) (b) \(\mathrm{CH}_{3}-\mathrm{CH}=\mathrm{C}=\mathrm{CH}_{2}\) (c) \(\mathrm{CH}_{3}-\mathrm{CH}_{2}-\mathrm{C} \equiv \mathrm{C}-\mathrm{H}\) (d)

Short Answer

Expert verified
Question: Identify the correct structure of the compound with the molecular formula C4H6 that fulfills the following properties: 1) Does not exist in cis or trans form. 2) Does not produce a precipitate with ammoniacal AgNO3 solution. 3) Optically inactive but a monohalogen derivative can be optically active. Answer: Option (b): CH3-CH=C=CH2

Step by step solution

01

Option (a): CH3C≡C-CH3

Alkynes do not exist in cis or trans forms. Since it's a symmetric molecule, it's optically inactive. Adding a halogen to the molecule results in the same symmetry, so the monohalogen derivative remains inactive. This option fulfills property 1 but not properties 2 and 3.
02

Option (b): CH3-CH=C=CH2

This is an allene molecule. Allenes cannot display cis or trans isomers. They don't react with ammoniacal AgNO3, fulfilling property 2. Although the molecule is optically inactive, adding a halogen to it results in an optically active derivative fulfilling property 3. Therefore, option (b) satisfies all the given properties.
03

Option (c): CH3-CH2-C≡C-H

Alkynes do not exist in cis or trans forms, fulfilling property 1. However, this molecule is optically inactive and its monohalogen derivatives are also optically inactive, not fulfilling property 3. It also doesn't fulfill property 2 about the precipitate formation.
04

Option (d): Not given

Since option (d) is not given in the exercise, we cannot analyze it. Putting all this information together, we can conclude that option (b) is the correct answer as it fulfills all the given properties of the compound C4H6.

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Most popular questions from this chapter

Directions: This section contains 1 paragraph. Based upon the paragraph, 3 multiple choice questions have to be answered. Each question has 4 choices (a), (b), (c) and (d), out of which ONLY ONE is correct. Passage I Alkenes undergo a variety of reactions like hydrogenation, halogenation, oxidation, epoxidation and so on. The double bond of the alkenes acts as electron donor. An unsaturated hydrocarbon gave, on treatment with alkaline \(\mathrm{KMnO}_{4}\) under hot conditions, one mole of adipic acid. The unsaturated hydrocarbon could be (a) \(\mathrm{H}_{3} \mathrm{C}-\mathrm{C} \equiv \mathrm{C}-\mathrm{CH}_{2}-\mathrm{CH}_{2}-\mathrm{CH}_{3}\) (b) \(\mathrm{H}_{3} \mathrm{C}-\mathrm{CH}_{2}-\mathrm{C} \equiv \mathrm{C}-\mathrm{CH}_{2}-\mathrm{CH}_{3}\)

Among the following which has the shortest C-C single bond length? (a) \(\mathrm{H}_{3} \mathrm{C}-\mathrm{CH}_{3}\) (b) \(\mathrm{H}_{2} \mathrm{C}=\mathrm{CH}-\mathrm{CH}=\mathrm{CH}_{2}\) (c) \(\mathrm{HC} \equiv \mathrm{C}-\mathrm{C} \equiv \mathrm{CH}\) (d) \(\mathrm{H}_{2} \mathrm{C}=\mathrm{CH}-\mathrm{CH}_{2}-\mathrm{CH}_{3}\)

This section contains multiple choice questions. Each question has 4 choices (a), (b), (c) and (d), out of which ONLY ONE is correct. Alkanes are chemically unreactive. However they undergo the type of reactions except (a) Halogenation (b) oxidation (c) addition (d) Nitration

(a) 4 -chloro- 1 -methylcyclohexane (b) trans 4 -chloro- 1 -methylcyclohexane (c) trans 1 -chloro-4-methylcyclohexane (d) trans 1 -methyl-4-chlorocyclohexane

Among the following compounds which one has more than one type of hybridization of carbon (a) \(\mathrm{H}_{2} \mathrm{C}=\mathrm{CH}-\mathrm{CH}=\mathrm{CH}_{2}\) (b) \(\mathrm{HC} \equiv \mathrm{C}-\mathrm{C} \equiv \mathrm{CH}\) (c) (d) \(\mathrm{CH}_{3} \mathrm{CH}_{2} \mathrm{COCH}\left(\mathrm{CH}_{3}\right)_{2}\)
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