Directions: Each question contains Statement-1 and Statement-2 and has the following choices (a), (b), (c) and (d), out of which ONLY ONE is correct. (a) Statement- 1 is True, Statement- 2 is True; Statement- 2 is a correct explanation for Statement-1 (b) Statement- 1 is True, Statement- 2 is True; Statement- 2 is NOT a correct explanation for Statement-1 (c) Statement-1 is True, Statement- 2 is False (d) Statement- 1 is False, Statement- 2 is True Statement 1 Oxymercuration reduction of an alkene gives an alcohol in which the -OH group is added to a more branched carbon of the double bond, while hydroboration- oxidation of an alkene gives an alcohol in which the -OH group is added to a less branched carbon of the alkene. and Statement 2 Hydration of an alkene in the presence of an acid is one of the standard methods of preparation of an alcohol form alkenes.

Short Answer

Expert verified
If so, does Statement 2 correctly explain Statement 1? Statement 1: Oxymercuration reduction and hydroboration-oxidation of alkenes result in the formation of alcohols with specific regioselectivities. Statement 2: Hydration of alkenes in the presence of an acid is a standard method of preparing alcohols from alkenes. Answer: (b) Statement- 1 is True, Statement- 2 is True; Statement- 2 is NOT a correct explanation for Statement-1.

Step by step solution

01

Statement 1: Oxymercuration reduction and hydroboration-oxidation of alkenes

We need to analyze the statement regarding the products of oxymercuration reduction and hydroboration-oxidation of alkenes. Oxymercuration reduction is a reaction that occurs in two steps: 1. Addition of mercury(II) acetate to the alkene, forming a mercurinium ion intermediate. 2. Reduction of the intermediate by sodium borohydride (NaBH4) to produce an alcohol, with the -OH group added to the more substituted carbon of the double bond (Markovnikov product). Hydroboration-oxidation is also a two-step reaction: 1. Addition of borane (BH3) to the alkene, forming a trialkylborane intermediate. 2. Oxidation of the intermediate by hydrogen peroxide (H2O2) in the presence of a hydroxide ion (OH-) to produce an alcohol, with the -OH group added to the less substituted carbon of the double bond (anti-Markovnikov product). Thus, Statement 1 is true, as it correctly mentions the regioselectivity of the two reactions involving alkenes.
02

Statement 2: Hydration of alkenes in the presence of an acid

We now need to analyze the statement about the hydration of an alkene in the presence of an acid being a standard method of preparing an alcohol from alkenes. Acid-catalyzed hydration involves the addition of water (H2O) across the double bond in the alkene, in the presence of a strong acid like sulfuric acid (H2SO4) as a catalyst. The hydroxyl group (-OH) is added to the more substituted carbon (Markovnikov rule) to produce the alcohol. This statement is also true, as acid-catalyzed hydration is indeed a standard method for preparing alcohols from alkenes.
03

Determine the correct answer choice

Now that we have determined that both statements are true, we need to find out if Statement 2 is a correct explanation for Statement 1 or not. Statement 1 discusses the regioselectivity of two different reactions (oxymercuration reduction and hydroboration-oxidation) involving alkenes, which ultimately result in the formation of alcohols. While Statement 2 mentions a different method of preparing an alcohol from an alkene (acid-catalyzed hydration), it does not explain why oxymercuration reduction and hydroboration-oxidation have their specific regioselectivities. Therefore, the correct answer choice is (b) Statement- 1 is True, Statement- 2 is True; Statement- 2 is NOT a correct explanation for Statement-1.

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